如何验证电话号码，以便它不允许所有相同的数字，如99999999999或11111111111在java

how to Validate a Phone number so that it should not allow all same numerics like 99999999999 or 11111111111 in JAVA

如何验证电话号码，以便它不允许所有相同的数字，如JAVA中的99999999999或11111111111

thanks Sunny Mate

谢谢Sunny Mate

3 个解决方案

#1

The following regex:

以下正则表达式：

^(\d)(?!\1+$)\d{10}$

matches 11 digit strings that do not have all the same digits.

匹配没有全部相同数字的11位数字符串。

A demo:

一个演示：

public class Main {
    public static void main(String[] args) throws Exception {
        String[] tests = {
                "11111111111",
                "99999999999",
                "99999999998",
                "12345678900"
        };
        for(String t : tests) {
            System.out.println(t+" :: "+t.matches("(\\d)(?!\\1+$)\\d{10}"));
        }
    }
}

which produces:

产生：

11111111111 :: false
99999999999 :: false
99999999998 :: true
12345678900 :: true

#2

If feasable, I'd try to discredit that requirement so it will be rejected.

如果可行，我会试图抹黑该要求，以免被拒绝。

No matter what you put into your plausibility checks, a user trying to avoid mandatory fields by entering junk into them will always succeed. You either end up having "smarter" harder-to-detect junk data items, or having a plausibility check which does not let all real-world data through into the system. Shit in, shit out. Build a shitshield, and your users will create fascies you never imagined.

无论你在合理性检查中加入什么，用户试图通过在其中输入垃圾来避免强制字段将始终成功。您要么最终拥有“更聪明”难以检测的垃圾数据项，要么进行合理性检查，不会让所有真实数据通过系统。屎，吐出来。构建一个shitshield，您的用户将创建您从未想象过的内容。

There is no way to program around that (except for simple things that usually are unintended, erraneously entered typos and so on).

没有办法围绕它编程（除了通常是无意识的简单事物，错误地输入错别字等）。

#3

This code matches numbers with at least 4 repeated numbers. (You could change the 3 in the regular expression to increase this threshold.)

此代码匹配至少包含4个重复数字的数字。（您可以更改正则表达式中的3以增加此阈值。）

Pattern sameDigits = Pattern.compile("(\\d)(\\1){3,}");

for (String num : new String[] {
        "11111",  // matches
        "1234",   // does not match
        "8584",   // does not match
        "999",    // does not match (too few repetitions)
        "9999"})  // matches

    if (sameDigits.matcher(num).matches())
        System.out.println("Same digits: " + num);
    else
        System.out.println("Not same digits: " + num);

Prints

打印

Same digits: 11111
Not same digits: 1234
Not same digits: 8584
Not same digits: 999
Same digits: 9999

#1