如何在java中生成随机的正数和负数

I am trying to generate random integers over the range (-32768, 32767) of the primitive data type short. The java Random object only generates positive numbers. How would I go about randomly creating numbers on that interval? Thanks.

我试图在原始数据类型short的范围(-32768,32767)上生成随机整数。 java Random对象仅生成正数。如何在该间隔内随机创建数字?谢谢。

8 个解决方案

#1

You random on (0, 32767+32768) then subtract by 32768

你随机(0,32767 + 32768)然后减去32768

#2

Random random=new Random();
int randomNumber=(random.nextInt(65536)-32768);

#3

public static int generatRandomPositiveNegitiveValue(int max , int min) {
    //Random rand = new Random();
    int ii = -min + (int) (Math.random() * ((max - (-min)) + 1));
    return ii;
}

#4

Generate numbers between 0 and 65535 then just subtract 32768

生成0到65535之间的数字,然后减去32768

#5

This is an old question I know but um....

这是一个我不知道的老问题,但是......

n=n-(n*2)

#6

([my double-compatible primitive type here])(Math.random() * [my max value here] * (Math.random() > 0.5 ? 1 : -1))

([我的双兼容原语类型])(Math.random()* [我的最大值] *(Math.random()> 0.5?1:-1))

example:

// need a random number between -500 and +500
long myRandomLong = (long)(Math.random() * 500 * (Math.random() > 0.5 ? 1 : -1));

#7

(Math.floor((Math.random() * 2)) > 0 ? 1 : -1) * Math.floor((Math.random() * 32767))

(Math.floor((Math.random()* 2))> 0?1:-1)* Math.floor((Math.random()* 32767))

#8

In case folks are interested in the double version (note this breaks down if passed MAX_VALUE or MIN_VALUE):

如果人们对双版本感兴趣(请注意,如果传递MAX_VALUE或MIN_VALUE则会出现故障):

private static final Random generator = new Random();
public static double random(double min, double max) {
    return min + (generator.nextDouble() * (max - min));
 }

#1