I asked a similar question about char to jsstring
... but now I have a problem with an int to jlongArray
, which I just can't figure out :/
我问了一个类似的问题关于char和jsstring…但是现在我有一个问题,一个int到jlongArray,我只是不知道:/。
I get the following error:
我得到了以下错误:
Error:(290, 10) error: cannot initialize a variable of type 'int *' with an rvalue of type 'jlong *' (aka 'long long *')
on this line:
在这条线:
JNIEXPORT void Java_de_meetspot_ndktest_MainActivity_LoadPlayerA(JNIEnv *javaEnvironment, jobject self, jstring audioPath, jlongArray offsetAndLength) {
const char* audio = javaEnvironment->GetStringUTFChars(audioPath, JNI_FALSE);
int* params = javaEnvironment->GetLongArrayElements(offsetAndLength, JNI_FALSE);
example->LoadPlayerA(audio, params);
}
this is the declaration:
这是声明:
void LoadPlayerA(const char *audioPath, int *params);
can someone help me out?
有人能帮我吗?
2 个解决方案
#1
2
long
in Java is a signed 64-bit integer type. A C++ int
on the other hand is only defined as being "guaranteed to have a width of at least 16 bits".
在Java中,long是一个有符号的64位整数类型。另一方面,C++ int被定义为“保证至少有16位的宽度”。
Lets's assume that your int
s are 32-bit (that's a very common scenario): so now you've got a pointer to a bunch of data where each element is 64 bits, and you're trying to pass that to a function that expects a pointer to 32-bit data. That's obviously not going to work, even if the compiler had allowed it.
假设您的ints是32位(这是一个非常常见的场景):所以现在您有了一个指向一堆数据的指针,其中每个元素都是64位,您正试图将其传递给一个函数,该函数期望指向32位数据的指针。这显然不会起作用,即使编译器允许。
Some options for you:
给你一些选项:
- Change
LoadPlayerA
to take ajlong*
orint64_t*
(and change any code inLoadPlayerA
that relies on the incoming data being of typeint
). - 更改LoadPlayerA以获取jlong*或int64_t*(并更改LoadPlayerA中的任何代码,该代码依赖于int类型的传入数据)。
- Change the Java code to pass the data as an
int[]
instead of along[]
, and changeLoadPlayerA
to take ajint*
orint32_t*
. - 更改Java代码以将数据传递为int[]而不是长[],并更改LoadPlayerA以获取jint*或int32_t*。
- Allocate an array/vector of type
int
in your JNI function and convert the data fromjlong
toint
before passing it toLoadPlayerA
. - 在JNI函数中分配int类型的数组/向量,并将数据从jlong转换为int,然后将其传递给LoadPlayerA。
#2
0
Thanks to Michael :) ..
感谢迈克尔:……
here is how i did it:
我是这样做的:
jlong *longParams = javaEnvironment->GetLongArrayElements(params, JNI_FALSE);
int arr[6];
for (int n = 0; n < 6; n++) arr[n] = longParams[n];
javaEnvironment->ReleaseLongArrayElements(params, longParams, JNI_ABORT);
#1
2
long
in Java is a signed 64-bit integer type. A C++ int
on the other hand is only defined as being "guaranteed to have a width of at least 16 bits".
在Java中,long是一个有符号的64位整数类型。另一方面,C++ int被定义为“保证至少有16位的宽度”。
Lets's assume that your int
s are 32-bit (that's a very common scenario): so now you've got a pointer to a bunch of data where each element is 64 bits, and you're trying to pass that to a function that expects a pointer to 32-bit data. That's obviously not going to work, even if the compiler had allowed it.
假设您的ints是32位(这是一个非常常见的场景):所以现在您有了一个指向一堆数据的指针,其中每个元素都是64位,您正试图将其传递给一个函数,该函数期望指向32位数据的指针。这显然不会起作用,即使编译器允许。
Some options for you:
给你一些选项:
- Change
LoadPlayerA
to take ajlong*
orint64_t*
(and change any code inLoadPlayerA
that relies on the incoming data being of typeint
). - 更改LoadPlayerA以获取jlong*或int64_t*(并更改LoadPlayerA中的任何代码,该代码依赖于int类型的传入数据)。
- Change the Java code to pass the data as an
int[]
instead of along[]
, and changeLoadPlayerA
to take ajint*
orint32_t*
. - 更改Java代码以将数据传递为int[]而不是长[],并更改LoadPlayerA以获取jint*或int32_t*。
- Allocate an array/vector of type
int
in your JNI function and convert the data fromjlong
toint
before passing it toLoadPlayerA
. - 在JNI函数中分配int类型的数组/向量,并将数据从jlong转换为int,然后将其传递给LoadPlayerA。
#2
0
Thanks to Michael :) ..
感谢迈克尔:……
here is how i did it:
我是这样做的:
jlong *longParams = javaEnvironment->GetLongArrayElements(params, JNI_FALSE);
int arr[6];
for (int n = 0; n < 6; n++) arr[n] = longParams[n];
javaEnvironment->ReleaseLongArrayElements(params, longParams, JNI_ABORT);