Ivar定义将“long”类型编码显示为“long long”类型编码

I've found what I think may be a bug with Ivar and Objective-C runtime. I'm using XCode 3.2.1 and associated libraries, developing a 64 bit app on X86_64 (MacBook Pro).

我发现我认为可能是Ivar和Objective-C运行时的错误。我正在使用XCode 3.2.1和相关库，在X86_64（MacBook Pro）上开发64位应用程序。

Where I would expect the type encoding for the following "longVal" to be 'l', the Ivar encoding is showing a 'q' (which is a 'long long').

我希望下面的“longVal”的类型编码为'l'，Ivar编码显示'q'（这是'long long'）。

Anyone else seeing this? Simplified code and output follows:

有人看到这个吗？简化的代码和输出如下：

Code:

码：

#import <Foundation/Foundation.h>
#import <objc/runtime.h>
@interface Bug : NSObject
{
    long        longVal;
    long long   longerVal;
}
@property (nonatomic,assign) long longVal;
@property (nonatomic,assign) long long longerVal;
@end

@implementation Bug

@synthesize longVal,longerVal;

@end


int main (int argc, const char * argv[]) {
    NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];
    unsigned int    ivarCount=0;
    Ivar *ivars= class_copyIvarList([Bug class], &ivarCount);

    for(unsigned int x=0;x<ivarCount;x++) {
        NSLog(@"Name [%@] encoding [%@]",
         [NSString stringWithCString:ivar_getName(ivars[x]) encoding:NSUTF8StringEncoding],
              [NSString stringWithCString:ivar_getTypeEncoding(ivars[x]) encoding:NSUTF8StringEncoding]);
    }

    [pool drain];
    return 0;
}

And here is output from debug console:

这是调试控制台的输出：

This GDB was configured as "x86_64-apple-darwin".tty /dev/ttys000
Loading program into debugger…
sharedlibrary apply-load-rules all
Program loaded.
run
[Switching to process 6048]
Running…
2010-03-17 22:16:29.138 ivarbug[6048:a0f] Name [longVal] encoding [q]
2010-03-17 22:16:29.146 ivarbug[6048:a0f] Name [longerVal] encoding [q]
(gdb) continue

Not a pretty picture!

不是一张漂亮的照片！

-- Frank

- 弗兰克

2 个解决方案

#1

It's not a bug. The GCC compiler, under a 64 bits architecture, chooses to represent longs as 64 bit integers. You can check it yourself:

这不是一个错误。在64位架构下，GCC编译器选择将long表示为64位整数。你可以自己检查一下：

printf("%lu\n", sizeof(long)); // will give "8"

As a reminder, the C standard only defines minimum sizes for integer types. long is only guaranteed to be at least 32 bits.

提醒一下，C标准仅定义整数类型的最小大小。 long仅保证至少为32位。

#2

Mac OS X, Linux and most other 64-bit operating systems use the LP64 model, where longs and pointers are 64 bits, while ints are 32 bits.

Mac OS X，Linux和大多数其他64位操作系统使用LP64模型，其中long和指针是64位，而int是32位。

#1