stoi导致超出范围错误

I have this code which gives me the error terminating with uncaught exception of type std::out_of_range: stoi: out of range

我有这个代码，它给我错误终止与类型std :: out_of_range的未捕获异常：stoi：超出范围

which I have identified as being caused by the line long ascii = std::stoi(temp_string);

我已经确定是由长行ascii = std :: stoi（temp_string）引起的;

what about the way i'm using stoi is causing that and how can I fix it?

我正在使用stoi的方式是什么造成的，我该如何解决？

std::string encode(std::string message){
std::string num_value;
long cipher;
if(message.length() < 20){
  for(int i = 0; i < message.length(); ++i){
    int temp = (char) message.at(i); 
    num_value += std::to_string(temp); 
  }
  return num_value;
}
else{
    int count = 0;   
    std::string temp_string;
    for(int i = 0; i < message.length(); ++i){
      int temp = (int)  message.at(i);
      temp_string += std::to_string(temp);           
      count++;   
       if(count == 20){
         count = 0;
         //add cipher encrypt
         long ascii = std::stoi(temp_string);
         //cipher = pow(ascii, 10000);
         //add n to cipther encrypt
         //add cipherencrypt + n to num_value
         //reset temp_string
         temp_string += "n";

         temp_string = ""; 

      }
 }
return num_value;
}

int main(){
  std::string s = "Hello World my t's your name aaaaaaaaaaaaa?";
  std::cout<<"encoded value : "<< encode(s)<<std::endl;
}

1 个解决方案

#1

std::stoi returns an integer; it sounds like your number is too large for an integer. Try using std::stol instead (see here).

std :: stoi返回一个整数;听起来你的数字对于一个整数来说太大了。尝试使用std :: stol（参见此处）。

Also if you intend for the code to be portable (useable with different compilers/platforms), keep in mind that integers and longs have no standard size. Unless the minimum size given by the standard is enough, you may want to look at using intX_t (where X is the size you want), as given in the cstdint header.

此外，如果您打算使代码可移植（可与不同的编译器/平台一起使用），请记住整数和长整数没有标准大小。除非标准给出的最小大小足够，否则您可能需要查看使用intX_t（其中X是您想要的大小），如cstdint标头中所示。