如何将相同类型的多个参数传递给jQuery Get

I'm trying to GET some data from a site using jQuery $.get. I need to set 2 parameters of the same type:

我正在尝试使用jQuery $. GET从站点获取一些数据。我需要设置2个相同类型的参数:

..&q=Some Text&q=Some other text

jQuery appears to be overwriting the first instance of q with the second and only sending 1. Any way around this?

jQuery似乎用第二个实例覆盖了第一个q实例，只发送了一个。解决这个问题的办法吗?

This is the code I was trying to use:

这就是我试图使用的代码:

var params = {
       "otherParam":"x",
       "q":text,
       "q":title
};
$.get(url, params, mySuccessFunction);

5 个解决方案

#1

Try:

试一试:

var params = {
  "otherParam": "x",
  "q": [ text, title ]
};

edit — more information: array-valued parameters like that are treated specially by jQuery. To appease many common server frameworks, by default (since release 1.5 or 1.6 I think) those will result in parameter names that include "[]" (open- and close-bracket characters) as a suffix (no number, contrary to my erroneous comment below). If you don't want that, you can set

编辑-更多信息:像这样的arrayvalue参数是由jQuery专门处理的。为了满足许多常见的服务器框架，默认情况下(我认为是1.5或1.6版本)，这些框架会导致参数名包括“[]”(开括号和右括号字符)作为后缀(没有数字，与我下面的错误注释相反)。如果你不想这样，你可以设置

jQuery.ajaxSettings.traditional = true;

and it'll just be "q" instead of "q[]".

它会是“q”而不是“q[]”。

#2

And another way to solve it that does not require encodeURIComponent() or messing with jQuery.ajaxSettings.traditional = true; which I would prefer not to do because I don't want to interfere (even temporarily) with what other parts of the site might be doing simultaneously.

另一种不需要encodeURIComponent()或使用jQuery.ajaxSettings的解决方法。传统= true;我宁愿不这样做，因为我不想(甚至是暂时地)干扰站点的其他部分可能同时进行的操作。

Is:

是:

 var params=[ 
       {name:"q", value:title},
       {name:"q", value:text}
 ];
 $.get(url, params, mySuccessFunction);

#3

Another approach without modifying jQuery.ajaxSettings.traditional = true; is to use $.param() http://api.jquery.com/jQuery.param/

不修改jQuery.ajaxSettings的另一种方法。传统= true;是要使用$.param() http://api.jquery.com/jQuery.param/

So something like this:

所以这样的:

var params = {
  "otherParam": "x",
  "q": [ text, title ]
};

$.get(url, $.param(params, true), mySuccessFunction);

#4

You can write the URL like this :

你可以这样写URL:

$.get(
   url+'?q='+encodeURIComponent(text)+'&q='+encodeURIComponent(title)+'&otherParam='+encodeURIComponent('x'),
   mySuccessFunction
);

#5

-1

Things are pretty simple and described in jQuery website http://api.jquery.com/jquery.param/.

jQuery网站http://api.jquery.com/jquery.param/描述的非常简单。

First create a params object

首先创建一个params对象

var params=[{
    name: 'param1',
    value: 'hello'
},
{
    name: 'param1',
    value: 'alex'
}];

next create the data to be sent to the service.

接下来创建要发送到服务的数据。

var data = jQuery.param(params);

That object can be inserted as the data param of the ajax request. I like using a settings object

该对象可以作为ajax请求的数据param插入。我喜欢使用settings对象

var settings={
    url: 'api/domain/timeline',
    type: 'get',
    contentType: 'application/json',
    data: data
    };
$.ajax(settings);

#1