I have some images in bin, I want to check the header to check the format (jpg, png, etc)
我在bin中有一些图像,我想检查标题以检查格式(jpg,png等)
I don't want to use temp files! I have a solution using TEMP FILES.
我不想使用临时文件!我有一个使用TEMP FILES的解决方案。
7 个解决方案
#1
21
The bits start with:
这些比特开始于:
$JPEG = "\xFF\xD8\xFF"
$GIF = "GIF"
$PNG = "\x89\x50\x4e\x47\x0d\x0a\x1a\x0a"
$BMP = "BM"
$PSD = "8BPS"
$SWF = "FWS"
The other ones I wouldn't know right now, but the big 3 (jpeg,gif,png) usually cover 99%. So, compare the first bytes to those string, and you have your answer.
其他我现在不知道的,但是大3(jpeg,gif,png)通常覆盖99%。因此,将第一个字节与这些字符串进行比较,您就得到了答案。
#2
27
I can se that most of you didn't understand the question :) ( question was how to validate binary data in buffer, not a file on disk).
我可以说大多数人都不明白这个问题:)(问题是如何验证缓冲区中的二进制数据,而不是磁盘上的文件)。
I had same problem, and resolved it with:
我有同样的问题,并解决了它:
$finfo = new finfo(FILEINFO_MIME_TYPE);
$finfo->buffer($rawImage);
#3
6
Here's an implementation of the function as described by Wrikken
这是Wrikken描述的函数的实现
function getImgType($filename) {
$handle = @fopen($filename, 'r');
if (!$handle)
throw new Exception('File Open Error');
$types = array('jpeg' => "\xFF\xD8\xFF", 'gif' => 'GIF', 'png' => "\x89\x50\x4e\x47\x0d\x0a", 'bmp' => 'BM', 'psd' => '8BPS', 'swf' => 'FWS');
$bytes = fgets($handle, 8);
$found = 'other';
foreach ($types as $type => $header) {
if (strpos($bytes, $header) === 0) {
$found = $type;
break;
}
}
fclose($handle);
return $found;
}
#4
1
Are the files being uploaded or are they already on the file system?
文件是上传还是已经在文件系统上?
Try using mime_content_type()
to get the file's MIME format.
尝试使用mime_content_type()来获取文件的MIME格式。
#5
1
http://php.net/manual/en/function.getimagesize.php
http://php.net/manual/en/function.getimagesize.php
"Index 2 is one of the IMAGETYPE_XXX constants indicating the type of the image."
“索引2是指示图像类型的IMAGETYPE_XXX常量之一。”
#6
0
Why not just check the file entension? :)
为什么不检查文件的扩展? :)
An Alternative
替代
if(exif_imagetype($filepath) == IMAGETYPE_JPEG){
echo 'This is a JPEG image';
}
#7
0
Use the fileinfo PHP extension:
使用fileinfo PHP扩展:
http://de.php.net/manual/en/function.finfo-file.php
http://de.php.net/manual/en/function.finfo-file.php
Its using the "file" *nix command to reliably determine the mime-type of a given file:
它使用“file”* nix命令可靠地确定给定文件的mime类型:
$finfo = finfo_open(FILEINFO_MIME_TYPE);
$mimetype = finfo_file($finfo, $filename);
finfo_close($finfo);
This extension is shipped with PHP 5.3 or can be installed from pecl (pecl install fileinfo) for earlier versions.
此扩展随PHP 5.3一起提供,或者可以从pecl(pecl install fileinfo)安装以用于早期版本。
#1
21
The bits start with:
这些比特开始于:
$JPEG = "\xFF\xD8\xFF"
$GIF = "GIF"
$PNG = "\x89\x50\x4e\x47\x0d\x0a\x1a\x0a"
$BMP = "BM"
$PSD = "8BPS"
$SWF = "FWS"
The other ones I wouldn't know right now, but the big 3 (jpeg,gif,png) usually cover 99%. So, compare the first bytes to those string, and you have your answer.
其他我现在不知道的,但是大3(jpeg,gif,png)通常覆盖99%。因此,将第一个字节与这些字符串进行比较,您就得到了答案。
#2
27
I can se that most of you didn't understand the question :) ( question was how to validate binary data in buffer, not a file on disk).
我可以说大多数人都不明白这个问题:)(问题是如何验证缓冲区中的二进制数据,而不是磁盘上的文件)。
I had same problem, and resolved it with:
我有同样的问题,并解决了它:
$finfo = new finfo(FILEINFO_MIME_TYPE);
$finfo->buffer($rawImage);
#3
6
Here's an implementation of the function as described by Wrikken
这是Wrikken描述的函数的实现
function getImgType($filename) {
$handle = @fopen($filename, 'r');
if (!$handle)
throw new Exception('File Open Error');
$types = array('jpeg' => "\xFF\xD8\xFF", 'gif' => 'GIF', 'png' => "\x89\x50\x4e\x47\x0d\x0a", 'bmp' => 'BM', 'psd' => '8BPS', 'swf' => 'FWS');
$bytes = fgets($handle, 8);
$found = 'other';
foreach ($types as $type => $header) {
if (strpos($bytes, $header) === 0) {
$found = $type;
break;
}
}
fclose($handle);
return $found;
}
#4
1
Are the files being uploaded or are they already on the file system?
文件是上传还是已经在文件系统上?
Try using mime_content_type()
to get the file's MIME format.
尝试使用mime_content_type()来获取文件的MIME格式。
#5
1
http://php.net/manual/en/function.getimagesize.php
http://php.net/manual/en/function.getimagesize.php
"Index 2 is one of the IMAGETYPE_XXX constants indicating the type of the image."
“索引2是指示图像类型的IMAGETYPE_XXX常量之一。”
#6
0
Why not just check the file entension? :)
为什么不检查文件的扩展? :)
An Alternative
替代
if(exif_imagetype($filepath) == IMAGETYPE_JPEG){
echo 'This is a JPEG image';
}
#7
0
Use the fileinfo PHP extension:
使用fileinfo PHP扩展:
http://de.php.net/manual/en/function.finfo-file.php
http://de.php.net/manual/en/function.finfo-file.php
Its using the "file" *nix command to reliably determine the mime-type of a given file:
它使用“file”* nix命令可靠地确定给定文件的mime类型:
$finfo = finfo_open(FILEINFO_MIME_TYPE);
$mimetype = finfo_file($finfo, $filename);
finfo_close($finfo);
This extension is shipped with PHP 5.3 or can be installed from pecl (pecl install fileinfo) for earlier versions.
此扩展随PHP 5.3一起提供,或者可以从pecl(pecl install fileinfo)安装以用于早期版本。