I am trying to initiate a TCP/IP connection using the standard library uIP. This code was taken directly from the manual, which shows how to open a new connection to a specific IP address (in this case my Windows localhost machine).
我正在尝试使用标准库uIP启动一个TCP/IP连接。这段代码直接取自手册，它展示了如何打开一个新的连接到一个特定的IP地址(在这里是我的Windows localhost机器)。
u16_t ipaddr[2];
uip_ipaddr(ipaddr, 127,0,0,1);
uip_connect(ipaddr, HTONS(51719));
But I am getting the following error:
但我得到了以下错误:
argument of type "u16_t *" is incompatible with parameter of type "u16_t [2]*"
shown for the last line (the uip_connect() function). What am I doing wrong? This is literally a cut-and-paste from the uIP reference manual.
显示最后一行(uip_connect()函数)。我做错了什么?这是来自uIP参考手册的剪切粘贴。
2 个解决方案
#1
1
The function uip_connect() requires an uip_ipaddr_t* type as its first argument.
函数uip_connect()需要一个uip_ipaddr_t*类型作为它的第一个参数。
uip_ipaddr_t is typedefed from uint16_t[2]. You have to pass the address of your array to get uip_ipaddr_t*
uip_ipaddr_t是从uint16_t[2]中输入的。您必须传递数组的地址以获得uip_ipaddr_t*。
#2
1
Notice that one is a 2D array u16_t [2]* while the other is a one dimensional array u16_t *. They are obviously not compatible.
注意，其中一个是一个2D数组u16_t[2]*，而另一个是一维数组u16_t *。它们显然不兼容。
#1
1
The function uip_connect() requires an uip_ipaddr_t* type as its first argument.
函数uip_connect()需要一个uip_ipaddr_t*类型作为它的第一个参数。
uip_ipaddr_t is typedefed from uint16_t[2]. You have to pass the address of your array to get uip_ipaddr_t*
uip_ipaddr_t是从uint16_t[2]中输入的。您必须传递数组的地址以获得uip_ipaddr_t*。
#2
1
Notice that one is a 2D array u16_t [2]* while the other is a one dimensional array u16_t *. They are obviously not compatible.
注意，其中一个是一个2D数组u16_t[2]*，而另一个是一维数组u16_t *。它们显然不兼容。