I'm attempting to create a simple generic node class that conforms to the Comparable protocol so that I can easily compare nodes without accessing their key. When I attempt to write the < and == functions, however, the compiler doesn't seem to like it. The < and == functions expect a type when defining the Node parameters. This was simple in Java where you defined equality and < internally to the class. Swift asks for it globally. Any thoughts ?
我正在尝试创建一个符合Comparable协议的简单通用节点类,以便我可以轻松地比较节点而无需访问其密钥。但是,当我尝试编写 <和==函数时,编译器似乎并不喜欢它。 <和="=函数在定义Node参数时需要一种类型。这在Java中很简单,您可以在其中定义相等性和<内部类。斯威夫特在全球范围内要求它。有什么想法吗" ?< p>
Example:
func < (lhs:Node<E:Comparable>, rhs:Node<E:Comparable>) -> Bool {
return lhs.key < rhs.key
}
func == (lhs:Node<E:Comparable>, rhs:Node<E:Comparable>) -> Bool {
return lhs.key == rhs.key
}
class Node<D:Comparable>: Comparable {
var key: D!
var next:Node?
var prev:Node?
init( key:D ) {
self.key = key
}
}
2 个解决方案
#1
8
You're close! The Node class already specifies that for Node<D>
, D
must conform to Comparable
. Therefore, Node<E: Comparable>
in the decl for ==
and <
is redundant. Instead, you want to restrict the types that the operators can be invoked upon:
你很亲密! Node类已经指定对于Node
func < <E: Comparable>(lhs: Node<E>, rhs: Node<E>) -> Bool {
return lhs.key < rhs.key
}
func == <E: Comparable>(lhs: Node<E>, rhs: Node<E>) -> Bool {
return lhs.key == rhs.key
}
class Node<D: Comparable>: Comparable {
var key: D!
var next: Node?
var prev: Node?
init(key: D) {
self.key = key
}
}
#2
2
You were very close. Small syntax issue Try this:
你非常接近。小语法问题试试这个:
class Node<D:Comparable>: Comparable {
var key: D!
var next:Node?
var prev:Node?
init( key:D ) {
self.key = key
}
}
func < <E:Comparable> (lhs:Node<E>, rhs:Node<E>) -> Bool {
return lhs.key < rhs.key
}
func == <E:Comparable> (lhs:Node<E>, rhs:Node<E>) -> Bool {
return lhs.key == rhs.key
}
#1
8
You're close! The Node class already specifies that for Node<D>
, D
must conform to Comparable
. Therefore, Node<E: Comparable>
in the decl for ==
and <
is redundant. Instead, you want to restrict the types that the operators can be invoked upon:
你很亲密! Node类已经指定对于Node
func < <E: Comparable>(lhs: Node<E>, rhs: Node<E>) -> Bool {
return lhs.key < rhs.key
}
func == <E: Comparable>(lhs: Node<E>, rhs: Node<E>) -> Bool {
return lhs.key == rhs.key
}
class Node<D: Comparable>: Comparable {
var key: D!
var next: Node?
var prev: Node?
init(key: D) {
self.key = key
}
}
#2
2
You were very close. Small syntax issue Try this:
你非常接近。小语法问题试试这个:
class Node<D:Comparable>: Comparable {
var key: D!
var next:Node?
var prev:Node?
init( key:D ) {
self.key = key
}
}
func < <E:Comparable> (lhs:Node<E>, rhs:Node<E>) -> Bool {
return lhs.key < rhs.key
}
func == <E:Comparable> (lhs:Node<E>, rhs:Node<E>) -> Bool {
return lhs.key == rhs.key
}