使用PHP在xml文档中获取特殊类型的子项

I'm looking for a way to get a special type of child out of a xml file with php. the xml:

我正在寻找一种方法,用PHP从xml文件中获取一个特殊类型的孩子。 xml:

<notify type="post" name="Max" />

I want to grab the name out of there. My code: `$sender =

我想把那个名字拿出来。我的代码:`$ sender =

    $sender = $node->getChild('notify');
    $sender = $sender->getChild('name');
    $sender = $sender->getData();

but as i expected it isn't working that way. Thanks in advance for any help

但正如我预期的那样,它并没有那样工作。在此先感谢您的帮助

1 个解决方案

#1

You can use an xpath expression to get the job done. It is like an SQL query for XML.

您可以使用xpath表达式来完成工作。它就像是XML的SQL查询。

$results = $xml->xpath("//notify[@type='post']/@name");

Assuming the XML in $xml, the expression reads like

假设$ xml中的XML,表达式如下

select all notify nodes, 
where their type-attribute is post,
give back the name-attribute.

$resultswill be an array, and my code example is made for simplexml. You can use the same xpath-expression with DOM though.

$ results将是一个数组,我的代码示例是针对simplexml。您可以使用与DOM相同的xpath-expression。

Here's the complete code:

这是完整的代码:

$x = <<<XML
<root>
    <notify type="post" name="Max" /> 
    <notify type="get" name="Lisa" /> 
    <notify type="post" name="William" /> 
</root>
XML;

$xml = simplexml_load_string($x);
$results = $xml->xpath("//notify[@type='post']/@name");
foreach ($results as $result) echo $result . "<br />";

Output:

Max
William

see it working: http://codepad.viper-7.com/eO29FK

看它工作:http://codepad.viper-7.com/eO29FK

#1