使用纬度和经度在swift中初始化CLLocation对象

In objective C (I have no experience with it) you can initialize a CLLocation object with latitude and longitude likes this:

在目标C（我没有经验）你可以初始化纬度和经度的CLLocation对象喜欢这样：

CLLocation *myLocation = [[CLLocation alloc]  initWithLatitude:your_latitiude_value longitude:your_longitude_value];

But how do I do it in Swift?

但是我如何在Swift中做到这一点？

I tried this,

我试过这个，

let loc_coords = CLLocationCoordinate2D(latitude: your_latitiude_value, longitude: your_longitude_value)

let loc = CLLocation().coordinate(loc_coords)

But I get this error:

但我得到这个错误：

Cannot invoke "coordinate" with an argument list of type '(CLLocationCoordiate2D)'

无法使用类型'（CLLocationCoordiate2D）'的参数列表调用“coordinate”

I need it to be a CLLocation object as I want to use the distanceFromLocation method within the locationManager.

我需要它作为CLLocation对象，因为我想在locationManager中使用distanceFromLocation方法。

Hope you can help, thanks!

希望你能帮忙，谢谢！

2 个解决方案

#1

I am not near my Mac to test it but the following should be working. Just pass your lat and lon values to the CLLocaion initializer like this:

我不是靠近我的Mac测试它，但以下应该工作。只需将lat和lon值传递给CLLocaion初始值设定项，如下所示：

let myLocation = CLLocation(latitude: your_latitiude_value, longitude: your_longitude_value)

For reference you can check the documentation

供参考，您可以查看文档

#2

If all you want is the initializer that takes a lat and long, your code can look like this:

如果你想要的只是一个lat和long的初始化器，你的代码可能如下所示：

let latitude: CLLocationDegrees = 37.2
let longitude: CLLocationDegrees = 22.9

let location: CLLocation = CLLocation(latitude: latitude, 
  longitude: longitude)

There are other initializers that take more parameters, but you didn't ask about those.

还有其他初始化程序需要更多参数，但您没有询问这些参数。

#1