将历元时间与毫秒转换为日期时间

I have used a ruby script to convert iso time stamp to epoch, the files that I am parsing has following time stamp structure:

我使用了一个ruby脚本将iso时间戳转换为epoch，我正在解析的文件有以下时间戳结构:

2009-03-08T00:27:31.807

Since I want to keep milliseconds I used following ruby code to convert it to epoch time:

由于我想保持毫秒，我使用了以下ruby代码将它转换成纪元时间:

irb(main):010:0> DateTime.parse('2009-03-08T00:27:31.807').strftime("%Q")
=> "1236472051807"

But In python I tried following:

但在python中，我尝试遵循:

import time 
time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(1236472051807))

But I don't get the original time date time back,

但是我没有得到最初的时间日期，

>>> time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(1236472051807))
'41152-03-29 02:50:07'
>>>

I wonder is it related to how I am formatting?

我想知道它是否与我的格式有关?

2 个解决方案

#1

Use datetime.datetime.fromtimestamp:

使用datetime.datetime.fromtimestamp:

>>> import datetime
>>> s = 1236472051807 / 1000.0
>>> datetime.datetime.fromtimestamp(s).strftime('%Y-%m-%d %H:%M:%S.%f')
'2009-03-08 09:27:31.807000'

%f directive is only supported by datetime.datetime.strftime, not by time.strftime.

%f指令仅受datetime.datetime支持。由time.strftime strftime,不是。

UPDATE Alternative using %, str.format:

使用%、str.format更新备选方案:

>>> import time
>>> s, ms = divmod(1236472051807, 1000)  # (1236472051, 807)
>>> '%s.%03d' % (time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(s)), ms)
'2009-03-08 00:27:31.807'
>>> '{}.{:03d}'.format(time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(s)), ms)
'2009-03-08 00:27:31.807'

#2

those are miliseconds, just divide them by 1000, since gmtime expects seconds ...

这些是毫秒，除以1000，因为gmtime期望秒…

time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(1236472051807/1000.0))

#1