Postgres:如何从unix epoch转换为日期?

时间:2022-02-11 16:00:15

The statement gives me the date and time.

声明给了我日期和时间。

How could I modify the statement so that it returns only the date?

我怎么能修改声明,使它只返回日期?

SELECT to_timestamp( TRUNC( CAST( epoch_ms AS bigint  ) / 1000 ) );

1 个解决方案

#1


45  

/* Current time */
 select now(); 

/* Epoch from current time;
   Epoch is number of seconds since 1970-01-01 00:00:00+00 */
 select extract(epoch from now()); 

/* Get back time from epoch */
 -- Option 1 - use to_timestamp function
 select to_timestamp( extract(epoch from now()));
 -- Option 2 - add seconds to 'epoch'
 select timestamp with time zone 'epoch' 
         + extract(epoch from now()) * interval '1 second';

/* Cast timestamp to date */
 -- Based on Option 1
 select to_timestamp(extract(epoch from now()))::date;
 -- Based on Option 2
 select (timestamp with time zone 'epoch' 
          + extract(epoch from now()) * interval '1 second')::date; 

 /* For column epoch_ms */
 select to_timestamp(extract(epoch epoch_ms))::date;

PostgreSQL Docs

PostgreSQL文档

#1


45  

/* Current time */
 select now(); 

/* Epoch from current time;
   Epoch is number of seconds since 1970-01-01 00:00:00+00 */
 select extract(epoch from now()); 

/* Get back time from epoch */
 -- Option 1 - use to_timestamp function
 select to_timestamp( extract(epoch from now()));
 -- Option 2 - add seconds to 'epoch'
 select timestamp with time zone 'epoch' 
         + extract(epoch from now()) * interval '1 second';

/* Cast timestamp to date */
 -- Based on Option 1
 select to_timestamp(extract(epoch from now()))::date;
 -- Based on Option 2
 select (timestamp with time zone 'epoch' 
          + extract(epoch from now()) * interval '1 second')::date; 

 /* For column epoch_ms */
 select to_timestamp(extract(epoch epoch_ms))::date;

PostgreSQL Docs

PostgreSQL文档