如何在swift中对结构进行排序?

I have an array of a struct and I would like to be able to sort it by either of the two variables using sort() if possible

我有一个结构体数组，如果可能的话，我希望能够使用sort()对它进行排序

struct{
    var deadline = 0
    var priority = 0
}

I looked at sort() in the documentation for the Swift programming language but it shows only simple arrays. can sort() be used or will I have to build my own?

我在Swift编程语言的文档中查看了sort()，但它只显示了简单的数组。我可以使用sort()或者我必须自己构建吗?

1 个解决方案

#1

Sort within the same array variable

Sort functions bellow are exactly the same, the only difference how short and expressive they are:

排序函数bellow是完全相同的，唯一的区别是它们的简短和表达性:

Full declaration:

全面声明:

myArr.sort { (lhs: EntryStruct, rhs: EntryStruct) -> Bool in
    // you can have additional code here
    return lhs.deadline < rhs.deadline
}

Shortened closure declaration:

缩短关闭声明:

myArr.sort { (lhs:EntryStruct, rhs:EntryStruct) in
    return lhs.deadline < rhs.deadline
}
// ... or even:
myArr.sort { (lhs, rhs) in return lhs.deadline < rhs.deadline }

Compact closure declaration:

紧凑的闭包声明:

myArr.sort { $0.deadline < $1.deadline }

Sort to a new array variable

Full declaration:

全面声明:

let newArr = myArr.sorted { (lhs: EntryStruct, rhs: EntryStruct) -> Bool in
    // you can have additional code here
    return lhs.deadline < rhs.deadline
}

Shortened closure declaration:

缩短关闭声明:

let newArr = myArr.sorted { (lhs:EntryStruct, rhs:EntryStruct) in
    return lhs.deadline < rhs.deadline
}
// ... or even:
let newArr = myArr.sorted { (lhs, rhs) in return lhs.deadline < rhs.deadline }

Compact closure declaration:

紧凑的闭包声明:

let newArr = myArr.sorted { $0.deadline < $1.deadline }