I have an array of objects, let's say:
我有一个对象数组,让我们说:
var objects = [
{name: 'A'},
{name: '1'},
{name: 'B'}
]
Knowing that I can sort it using Lodash sortBy:
知道我可以使用Lodash sortBy对它进行排序:
objects= _.sortBy(objects, 'name')
which will result in this:
这将导致:
[
{name: '1'},
{name: 'A'},
{name: 'B'}
]
But my desired output is this:
但我想要的输出是这样的:
[
{name: 'A'},
{name: 'B'},
{name: '1'}
]
Please help.
请帮忙。
5 个解决方案
#1
6
Using Array#sort
you can apply this logic:
使用Array#sort您可以应用此逻辑:
// If both are numbers or both are not numbers
isNaN(a.name) === isNaN(b.name) ?
// then compare between them
a.name.localeCompare(b.name)
: // else
// If the 1st is not a number move it up, if it's a number move it down
(isNaN(a.name) ? -1 : 1);
Without lodash:
没有lodash:
var objects = [{"name":"A"},{"name":"3"},{"name":"1"},{"name":"B"}];
objects.sort(function(a, b) {
return isNaN(a.name) === isNaN(b.name) ? a.name.localeCompare(b.name) : (isNaN(a.name) ? -1 : 1);
});
console.log(objects);
As part of a lodash's chain:
作为lodash链的一部分:
var objects = [{"name":"A"},{"name":"3"},{"name":"1"},{"name":"B"}];
var result = _(objects)
.sort(function(a, b) {
return isNaN(a.name) === isNaN(b.name) ? a.name.localeCompare(b.name) : (isNaN(a.name) ? -1 : 1);
})
.value();
console.log(result);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.3/lodash.min.js"></script>
#2
2
I'm not sure if using lodash's sortBy
is the correct approach for this problem. Here's an implementation using Javascript's Array#sort
method.
我不确定使用lodash的sortBy是否是解决此问题的正确方法。这是使用Javascript的Array#排序方法的实现。
It takes not only the first character but the entire string into account when doing the sorting.
在进行排序时,不仅要考虑第一个字符,还要考虑整个字符串。
const objects = [{
name: '2'
}, {
name: 'B'
}, {
name: '1'
}, {
name: 'A'
}, {
name: 'A1'
}, {
name: 'AA'
}]
objects.sort((o1, o2) => {
let a = o1.name, b = o2.name;
let isDigit = x => x >= 48 && x <= 57;
for (let i = 0, n = Math.min(a.length, b.length); i < n; i++) {
let aCharCode = a.charCodeAt(i), bCharCode = b.charCodeAt(i);
if (aCharCode !== bCharCode) {
if (isDigit(aCharCode) && !isDigit(bCharCode)) return 1;
if (isDigit(bCharCode) && !isDigit(aCharCode)) return -1;
return aCharCode - bCharCode;
}
}
return a.length - b.length;
});
console.log(objects)
For the given input, this prints out
对于给定的输入,打印出来
[
{
"name": "A"
},
{
"name": "AA"
},
{
"name": "A1"
},
{
"name": "B"
},
{
"name": "1"
},
{
"name": "2"
}
]
#3
1
Solution with two _.sortBy()
One for priotizing alphabets first, then another one for sorting the elements.
一个用于首先打印字母,然后另一个用于对元素进行排序。
In my opinion it's more readable and it will have no performance impact.
在我看来,它更具可读性,不会对性能产生影响。
const objects = [
{name: 'B'},
{name: '2'},
{name: '1'},
{name: 'A'}
]
const result = _.sortBy(_.sortBy(objects, o => !isNaN(parseInt(o.name)), 'name'))
console.log(result)
<script src="https://lodash.com/vendor/cdn.jsdelivr.net/lodash/4.17.3/lodash.min.js"></script>
#4
1
Partition the input, sort separately and join back:
对输入进行分区,单独排序并加入:
Code:
码:
const _ = require('lodash');
const customSort = (a) => _.chain(_.partition(a, i => isNaN(i.name))).flatMap(p => _.sortBy(p, 'name')).value();
const input = [
{ name: '1' },
{ name: 'A' },
{ name: '6' },
{ name: 'B' },
{ name: 'a' },
{ name: '0' },
{ name: '3' }];
console.log(customSort(input));
Output:
输出:
[ { name: 'A' },
{ name: 'B' },
{ name: 'a' },
{ name: '0' },
{ name: '1' },
{ name: '3' },
{ name: '6' } ]
#5
1
If name
is an integer prefix it with z
for comparison.
如果name是整数前缀,则使用z进行比较。
var objects = [
{name: 'z'},
{name: 'A'},
{name: '1'},
{name: 'B'}
], sorted = _.sortBy( objects, [
function(d) {
return !isNaN(parseFloat(d.name))
&& isFinite(d.name)
? 'z' + d.name
: d.name;
}
]
);
console.log(sorted);
<script src="https://lodash.com/vendor/cdn.jsdelivr.net/lodash/4.17.3/lodash.min.js"></script>
#1
6
Using Array#sort
you can apply this logic:
使用Array#sort您可以应用此逻辑:
// If both are numbers or both are not numbers
isNaN(a.name) === isNaN(b.name) ?
// then compare between them
a.name.localeCompare(b.name)
: // else
// If the 1st is not a number move it up, if it's a number move it down
(isNaN(a.name) ? -1 : 1);
Without lodash:
没有lodash:
var objects = [{"name":"A"},{"name":"3"},{"name":"1"},{"name":"B"}];
objects.sort(function(a, b) {
return isNaN(a.name) === isNaN(b.name) ? a.name.localeCompare(b.name) : (isNaN(a.name) ? -1 : 1);
});
console.log(objects);
As part of a lodash's chain:
作为lodash链的一部分:
var objects = [{"name":"A"},{"name":"3"},{"name":"1"},{"name":"B"}];
var result = _(objects)
.sort(function(a, b) {
return isNaN(a.name) === isNaN(b.name) ? a.name.localeCompare(b.name) : (isNaN(a.name) ? -1 : 1);
})
.value();
console.log(result);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.3/lodash.min.js"></script>
#2
2
I'm not sure if using lodash's sortBy
is the correct approach for this problem. Here's an implementation using Javascript's Array#sort
method.
我不确定使用lodash的sortBy是否是解决此问题的正确方法。这是使用Javascript的Array#排序方法的实现。
It takes not only the first character but the entire string into account when doing the sorting.
在进行排序时,不仅要考虑第一个字符,还要考虑整个字符串。
const objects = [{
name: '2'
}, {
name: 'B'
}, {
name: '1'
}, {
name: 'A'
}, {
name: 'A1'
}, {
name: 'AA'
}]
objects.sort((o1, o2) => {
let a = o1.name, b = o2.name;
let isDigit = x => x >= 48 && x <= 57;
for (let i = 0, n = Math.min(a.length, b.length); i < n; i++) {
let aCharCode = a.charCodeAt(i), bCharCode = b.charCodeAt(i);
if (aCharCode !== bCharCode) {
if (isDigit(aCharCode) && !isDigit(bCharCode)) return 1;
if (isDigit(bCharCode) && !isDigit(aCharCode)) return -1;
return aCharCode - bCharCode;
}
}
return a.length - b.length;
});
console.log(objects)
For the given input, this prints out
对于给定的输入,打印出来
[
{
"name": "A"
},
{
"name": "AA"
},
{
"name": "A1"
},
{
"name": "B"
},
{
"name": "1"
},
{
"name": "2"
}
]
#3
1
Solution with two _.sortBy()
One for priotizing alphabets first, then another one for sorting the elements.
一个用于首先打印字母,然后另一个用于对元素进行排序。
In my opinion it's more readable and it will have no performance impact.
在我看来,它更具可读性,不会对性能产生影响。
const objects = [
{name: 'B'},
{name: '2'},
{name: '1'},
{name: 'A'}
]
const result = _.sortBy(_.sortBy(objects, o => !isNaN(parseInt(o.name)), 'name'))
console.log(result)
<script src="https://lodash.com/vendor/cdn.jsdelivr.net/lodash/4.17.3/lodash.min.js"></script>
#4
1
Partition the input, sort separately and join back:
对输入进行分区,单独排序并加入:
Code:
码:
const _ = require('lodash');
const customSort = (a) => _.chain(_.partition(a, i => isNaN(i.name))).flatMap(p => _.sortBy(p, 'name')).value();
const input = [
{ name: '1' },
{ name: 'A' },
{ name: '6' },
{ name: 'B' },
{ name: 'a' },
{ name: '0' },
{ name: '3' }];
console.log(customSort(input));
Output:
输出:
[ { name: 'A' },
{ name: 'B' },
{ name: 'a' },
{ name: '0' },
{ name: '1' },
{ name: '3' },
{ name: '6' } ]
#5
1
If name
is an integer prefix it with z
for comparison.
如果name是整数前缀,则使用z进行比较。
var objects = [
{name: 'z'},
{name: 'A'},
{name: '1'},
{name: 'B'}
], sorted = _.sortBy( objects, [
function(d) {
return !isNaN(parseFloat(d.name))
&& isFinite(d.name)
? 'z' + d.name
: d.name;
}
]
);
console.log(sorted);
<script src="https://lodash.com/vendor/cdn.jsdelivr.net/lodash/4.17.3/lodash.min.js"></script>