如何使用std::sort对c++中的数组进行排序

时间:2021-02-04 15:56:10

How to use standard template library std::sort() to sort an array declared as int v[2000];

如何使用标准模板库std::sort()对声明为int v的数组进行排序[2000];

Does C++ provide some function that can get the begin and end index of an array?

c++是否提供了一些函数来获取数组的开始和结束索引?

11 个解决方案

#1


90  

In C++0x/11 we get std::begin and std::end which are overloaded for arrays:

在c++ 0x/11中,我们得到std: begin和std::end,它们对数组来说是重载的:

#include <algorithm>

int main(){
  int v[2000];
  std::sort(std::begin(v), std::end(v));
}

If you don't have access to C++0x, it isn't hard to write them yourself:

如果您没有c++ 0x的访问权限,那么您可以自己编写:

// for container with nested typedefs, non-const version
template<class Cont>
typename Cont::iterator begin(Cont& c){
  return c.begin();
}

template<class Cont>
typename Cont::iterator end(Cont& c){
  return c.end();
}

// const version
template<class Cont>
typename Cont::const_iterator begin(Cont const& c){
  return c.begin();
}

template<class Cont>
typename Cont::const_iterator end(Cont const& c){
  return c.end();
}

// overloads for C style arrays
template<class T, std::size_t N>
T* begin(T (&arr)[N]){
  return &arr[0];
}

template<class T, std::size_t N>
T* end(T (&arr)[N]){
  return arr + N;
}

#2


60  

#include <algorithm>
static const size_t v_size = 2000;
int v[v_size];
// Fill the array by values
std::sort(v,v+v_size); 

In C++11:

在c++中11:

#include <algorithm>
#include <array>
std::array<int, 2000> v;
// Fill the array by values
std::sort(v.begin(),v.end()); 

#3


26  

If you don't know the size, you can use:

如果你不知道尺寸,你可以用:

std::sort(v, v + sizeof v / sizeof v[0]);

Even if you do know the size, it's a good idea to code it this way as it will reduce the possibility of a bug if the array size is changed later.

即使您知道它的大小,以这种方式编写它也是一个好主意,因为如果稍后更改数组大小,它将减少出现错误的可能性。

#4


15  

You can sort it std::sort(v, v + 2000)

你可以对它进行排序:sort(v, v + 2000)

#5


3  

//It is working
#include<iostream>
using namespace std;
void main()
{
    int a[5];
    int temp=0;
    cout<<"Enter Values"<<endl;
    for(int i=0;i<5;i++)
    {
        cin>>a[i];
    }
    for(int i=0;i<5;i++)
    {
        for(int j=0;j<5;j++)
        {
            if(a[i]>a[j])
            {
                temp=a[i];
                a[i]=a[j];
                a[j]=temp;
            }
        }
    }
    cout<<"Asending Series"<<endl;
    for(int i=0;i<5;i++)
    {
        cout<<endl;
        cout<<a[i]<<endl;
    }


    for(int i=0;i<5;i++)
    {
        for(int j=0;j<5;j++)
        {
            if(a[i]<a[j])
            {
                temp=a[i];
                a[i]=a[j];
                a[j]=temp;
            }
        }
    }
    cout<<"Desnding Series"<<endl;
    for(int i=0;i<5;i++)
    {
        cout<<endl;
        cout<<a[i]<<endl;
    }


}

#6


2  

you can use sort() in C++ STL. sort() function Syntax :

您可以在c++ STL中使用sort()。()函数的语法:

 sort(array_name, array_name+size)      

 So you use  sort(v, v+2000);

#7


2  

C++ sorting using sort function

c++排序函数

#include <bits/stdc++.h>
 using namespace std;

vector <int> v[100];

int main()
{
  sort(v.begin(), v.end());
}

#8


0  

sorting method without std::sort:

排序方法没有std:::

// sorting myArray ascending
int iTemp = 0;
for (int i = 0; i < ARRAYSIZE; i++)
{
    for (int j = i + 1; j <= ARRAYSIZE; j++)
    {
        // for descending sort change '<' with '>'
        if (myArray[j] < myArray[i])
        {
            iTemp = myArray[i];
            myArray[i] = myArray[j];
            myArray[j] = iTemp;
        }
    }
}

Run complete example:

运行完整的示例:

#include <iostream> // std::cout, std::endl /* http://en.cppreference.com/w/cpp/header/iostream */
#include <cstdlib>  // srand(), rand()      /* http://en.cppreference.com/w/cpp/header/cstdlib */
#include <ctime>    // time()               /* http://en.cppreference.com/w/cpp/header/ctime */


int main()
{
    const int ARRAYSIZE = 10;
    int myArray[ARRAYSIZE];

    // populate myArray with random numbers from 1 to 1000
    srand(time(0));
    for (int i = 0; i < ARRAYSIZE; i++)
    {
        myArray[i] = rand()% 1000 + 1;
    }

    // print unsorted myArray
    std::cout << "unsorted myArray: " << std::endl;
    for (int i = 0; i < ARRAYSIZE; i++)
    {
        std::cout << "[" << i << "] -> " << myArray[i] << std::endl;
    }
    std::cout << std::endl;

    // sorting myArray ascending
    int iTemp = 0;
    for (int i = 0; i < ARRAYSIZE; i++)
    {
        for (int j = i + 1; j <= ARRAYSIZE; j++)
        {
            // for descending sort change '<' with '>'
            if (myArray[j] < myArray[i])
            {
                iTemp = myArray[i];
                myArray[i] = myArray[j];
                myArray[j] = iTemp;
            }
        }
    }

    // print sorted myArray
    std::cout << "sorted myArray: " << std::endl;
    for (int i = 0; i < ARRAYSIZE; i++)
    {
        std::cout << "[" << i << "] -> " << myArray[i] << std::endl;
    }
    std::cout << std::endl;

    return 0;
}

#9


0  

Use the C++ std::sort function:

使用c++ std::排序函数:

#include <algorithm>
using namespace std;

int main()
{
  vector<int> v(2000);
  sort(v.begin(), v.end());
}

#10


0  

It is as simple as that.....c++ is providing you a built-in function in STL(Standard Template Library) called sort(arr_name ,arr_name+arr_size) which runs 20% to 50% faster than the hand-coded quick-sort. Also you better include the header file

就是这么简单……c++在STL(标准模板库)中提供了一个名为sort(arr_name,arr_name+arr_size)的内置函数,比手工编写的快速排序快20%到50%。您还应该包括头文件。

#include<bits/stdc++.h>

Here is the sample code for it's usage:

下面是使用的示例代码:

#include<isostream>
#include<bits/stdc++.h>
using namespace std;
main()
{
    int n;cin>>n;
    int a[n];
    for(int i=0;i<n;i++)
        cin>>a[i];
    sort(a,a+n);
    for(int i=0;i<n;i++)
        cout<<a[i]<<" ";
}

#11


-1  

you can use,

您可以使用,

 std::sort(v.begin(),v.end());

#1


90  

In C++0x/11 we get std::begin and std::end which are overloaded for arrays:

在c++ 0x/11中,我们得到std: begin和std::end,它们对数组来说是重载的:

#include <algorithm>

int main(){
  int v[2000];
  std::sort(std::begin(v), std::end(v));
}

If you don't have access to C++0x, it isn't hard to write them yourself:

如果您没有c++ 0x的访问权限,那么您可以自己编写:

// for container with nested typedefs, non-const version
template<class Cont>
typename Cont::iterator begin(Cont& c){
  return c.begin();
}

template<class Cont>
typename Cont::iterator end(Cont& c){
  return c.end();
}

// const version
template<class Cont>
typename Cont::const_iterator begin(Cont const& c){
  return c.begin();
}

template<class Cont>
typename Cont::const_iterator end(Cont const& c){
  return c.end();
}

// overloads for C style arrays
template<class T, std::size_t N>
T* begin(T (&arr)[N]){
  return &arr[0];
}

template<class T, std::size_t N>
T* end(T (&arr)[N]){
  return arr + N;
}

#2


60  

#include <algorithm>
static const size_t v_size = 2000;
int v[v_size];
// Fill the array by values
std::sort(v,v+v_size); 

In C++11:

在c++中11:

#include <algorithm>
#include <array>
std::array<int, 2000> v;
// Fill the array by values
std::sort(v.begin(),v.end()); 

#3


26  

If you don't know the size, you can use:

如果你不知道尺寸,你可以用:

std::sort(v, v + sizeof v / sizeof v[0]);

Even if you do know the size, it's a good idea to code it this way as it will reduce the possibility of a bug if the array size is changed later.

即使您知道它的大小,以这种方式编写它也是一个好主意,因为如果稍后更改数组大小,它将减少出现错误的可能性。

#4


15  

You can sort it std::sort(v, v + 2000)

你可以对它进行排序:sort(v, v + 2000)

#5


3  

//It is working
#include<iostream>
using namespace std;
void main()
{
    int a[5];
    int temp=0;
    cout<<"Enter Values"<<endl;
    for(int i=0;i<5;i++)
    {
        cin>>a[i];
    }
    for(int i=0;i<5;i++)
    {
        for(int j=0;j<5;j++)
        {
            if(a[i]>a[j])
            {
                temp=a[i];
                a[i]=a[j];
                a[j]=temp;
            }
        }
    }
    cout<<"Asending Series"<<endl;
    for(int i=0;i<5;i++)
    {
        cout<<endl;
        cout<<a[i]<<endl;
    }


    for(int i=0;i<5;i++)
    {
        for(int j=0;j<5;j++)
        {
            if(a[i]<a[j])
            {
                temp=a[i];
                a[i]=a[j];
                a[j]=temp;
            }
        }
    }
    cout<<"Desnding Series"<<endl;
    for(int i=0;i<5;i++)
    {
        cout<<endl;
        cout<<a[i]<<endl;
    }


}

#6


2  

you can use sort() in C++ STL. sort() function Syntax :

您可以在c++ STL中使用sort()。()函数的语法:

 sort(array_name, array_name+size)      

 So you use  sort(v, v+2000);

#7


2  

C++ sorting using sort function

c++排序函数

#include <bits/stdc++.h>
 using namespace std;

vector <int> v[100];

int main()
{
  sort(v.begin(), v.end());
}

#8


0  

sorting method without std::sort:

排序方法没有std:::

// sorting myArray ascending
int iTemp = 0;
for (int i = 0; i < ARRAYSIZE; i++)
{
    for (int j = i + 1; j <= ARRAYSIZE; j++)
    {
        // for descending sort change '<' with '>'
        if (myArray[j] < myArray[i])
        {
            iTemp = myArray[i];
            myArray[i] = myArray[j];
            myArray[j] = iTemp;
        }
    }
}

Run complete example:

运行完整的示例:

#include <iostream> // std::cout, std::endl /* http://en.cppreference.com/w/cpp/header/iostream */
#include <cstdlib>  // srand(), rand()      /* http://en.cppreference.com/w/cpp/header/cstdlib */
#include <ctime>    // time()               /* http://en.cppreference.com/w/cpp/header/ctime */


int main()
{
    const int ARRAYSIZE = 10;
    int myArray[ARRAYSIZE];

    // populate myArray with random numbers from 1 to 1000
    srand(time(0));
    for (int i = 0; i < ARRAYSIZE; i++)
    {
        myArray[i] = rand()% 1000 + 1;
    }

    // print unsorted myArray
    std::cout << "unsorted myArray: " << std::endl;
    for (int i = 0; i < ARRAYSIZE; i++)
    {
        std::cout << "[" << i << "] -> " << myArray[i] << std::endl;
    }
    std::cout << std::endl;

    // sorting myArray ascending
    int iTemp = 0;
    for (int i = 0; i < ARRAYSIZE; i++)
    {
        for (int j = i + 1; j <= ARRAYSIZE; j++)
        {
            // for descending sort change '<' with '>'
            if (myArray[j] < myArray[i])
            {
                iTemp = myArray[i];
                myArray[i] = myArray[j];
                myArray[j] = iTemp;
            }
        }
    }

    // print sorted myArray
    std::cout << "sorted myArray: " << std::endl;
    for (int i = 0; i < ARRAYSIZE; i++)
    {
        std::cout << "[" << i << "] -> " << myArray[i] << std::endl;
    }
    std::cout << std::endl;

    return 0;
}

#9


0  

Use the C++ std::sort function:

使用c++ std::排序函数:

#include <algorithm>
using namespace std;

int main()
{
  vector<int> v(2000);
  sort(v.begin(), v.end());
}

#10


0  

It is as simple as that.....c++ is providing you a built-in function in STL(Standard Template Library) called sort(arr_name ,arr_name+arr_size) which runs 20% to 50% faster than the hand-coded quick-sort. Also you better include the header file

就是这么简单……c++在STL(标准模板库)中提供了一个名为sort(arr_name,arr_name+arr_size)的内置函数,比手工编写的快速排序快20%到50%。您还应该包括头文件。

#include<bits/stdc++.h>

Here is the sample code for it's usage:

下面是使用的示例代码:

#include<isostream>
#include<bits/stdc++.h>
using namespace std;
main()
{
    int n;cin>>n;
    int a[n];
    for(int i=0;i<n;i++)
        cin>>a[i];
    sort(a,a+n);
    for(int i=0;i<n;i++)
        cout<<a[i]<<" ";
}

#11


-1  

you can use,

您可以使用,

 std::sort(v.begin(),v.end());