I have the following python program:
我有以下python程序:
#!/usr/bin/env python
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('arg', choices=['foo', 'bar', 'baz'], default='foo', nargs='*')
args = parser.parse_args()
print(args)
If I invoke the program like this:
如果我像这样调用程序:
./prog.py
the output is
输出是
Namespace(arg='foo')
But if I invoke the program with foo
as an argument:
但是如果我用foo调用程序作为参数:
./prog.py foo
the output is
输出是
Namespace(arg=['foo'])
Question
问题
How can I get arg
's default value to become a list
?
如何使arg的默认值变成列表?
I've tried
我试过了
I've tried setting default=['foo']
but that results in:
我试过设置default=['foo'],但结果是:
prog.py: error: argument arg: invalid choice: ['foo'] (choose from 'foo', 'bar', 'baz')
1 个解决方案
#1
5
This is a duplicate of an old, but open, bug/issue
这是一个旧的,但开放的bug/问题的副本
http://bugs.python.org/issue9625 (argparse: Problem with defaults for variable nargs when using choices
)
http://bugs.python.org/issue9625 (argparse:使用选项时变量nargs的默认问题)
A positional
with *
gets some special handling. Its default is always passed through the choices
test if you don't provide values.
带有*的位置会得到一些特殊的处理。如果不提供值,它的默认值总是通过选择测试。
Compare that with the case of an optional
与可选的情况相比
In [138]: p=argparse.ArgumentParser()
In [139]: a=p.add_argument('--arg',choices=['foo','bar','baz'],nargs='*')
In [140]: p.parse_args([])
Out[140]: Namespace(arg=None)
In [141]: a.default=['foo']
In [142]: p.parse_args([])
Out[142]: Namespace(arg=['foo'])
The default is accepted without testing:
未经测试,默认为:
In [143]: a.default=['xxx']
In [144]: p.parse_args([])
Out[144]: Namespace(arg=['xxx'])
The relevant code is:
相关的代码是:
def _get_values(self, action, arg_strings):
...
# when nargs='*' on a positional, if there were no command-line
# args, use the default if it is anything other than None
elif (not arg_strings and action.nargs == ZERO_OR_MORE and
not action.option_strings):
if action.default is not None:
value = action.default
else:
value = arg_strings
self._check_value(action, value)
The proposed bug/issue patch makes a small change to this block of code.
提出的bug/问题补丁对这段代码做了一个小的修改。
#1
5
This is a duplicate of an old, but open, bug/issue
这是一个旧的,但开放的bug/问题的副本
http://bugs.python.org/issue9625 (argparse: Problem with defaults for variable nargs when using choices
)
http://bugs.python.org/issue9625 (argparse:使用选项时变量nargs的默认问题)
A positional
with *
gets some special handling. Its default is always passed through the choices
test if you don't provide values.
带有*的位置会得到一些特殊的处理。如果不提供值,它的默认值总是通过选择测试。
Compare that with the case of an optional
与可选的情况相比
In [138]: p=argparse.ArgumentParser()
In [139]: a=p.add_argument('--arg',choices=['foo','bar','baz'],nargs='*')
In [140]: p.parse_args([])
Out[140]: Namespace(arg=None)
In [141]: a.default=['foo']
In [142]: p.parse_args([])
Out[142]: Namespace(arg=['foo'])
The default is accepted without testing:
未经测试,默认为:
In [143]: a.default=['xxx']
In [144]: p.parse_args([])
Out[144]: Namespace(arg=['xxx'])
The relevant code is:
相关的代码是:
def _get_values(self, action, arg_strings):
...
# when nargs='*' on a positional, if there were no command-line
# args, use the default if it is anything other than None
elif (not arg_strings and action.nargs == ZERO_OR_MORE and
not action.option_strings):
if action.default is not None:
value = action.default
else:
value = arg_strings
self._check_value(action, value)
The proposed bug/issue patch makes a small change to this block of code.
提出的bug/问题补丁对这段代码做了一个小的修改。