my output required in the column name is now i am getting as
列名称中我需要的输出现在是我得到的
Column A Column B
x = 128
Y = 145
in the code as we need to write is "Column A (N=x)" "Column B (N=Y)"
How we will call the value in X in quotation mark.
but i need the column name as below
Column A Column B
(N=128) (N=145)
how we need to create this Could someone help me to figure this out?
我们如何创建这个可以有人帮我解决这个问题吗?
1 个解决方案
#1
1
You could use paste
or sprintf
你可以使用paste或sprintf
names(df1) <- paste0(names(df1), ' (N=', c(x,Y), ')')
names(df1)
#[1] "Column A (N=128)" "Column B (N=145)"
It may be better to keep it in a single line instead of multi-line column names. For printing, we can use cat
将它保持在一行而不是多行列名称可能更好。对于打印,我们可以使用猫
cat(paste0(names(df1), '\n (N=', c(x,Y), ')\n'))
data
df1 <- data.frame("Column A" =1:5, "Column B"= 6:10, check.names=FALSE)
x <- 128
Y <- 145
#1
1
You could use paste
or sprintf
你可以使用paste或sprintf
names(df1) <- paste0(names(df1), ' (N=', c(x,Y), ')')
names(df1)
#[1] "Column A (N=128)" "Column B (N=145)"
It may be better to keep it in a single line instead of multi-line column names. For printing, we can use cat
将它保持在一行而不是多行列名称可能更好。对于打印,我们可以使用猫
cat(paste0(names(df1), '\n (N=', c(x,Y), ')\n'))
data
df1 <- data.frame("Column A" =1:5, "Column B"= 6:10, check.names=FALSE)
x <- 128
Y <- 145