总结字典中的值

I created a dictionary with the following syntax

我用以下语法创建了一个字典

frequency_m= dict(zip(unique, counts))

which results into:

结果如下:

{0: 3512488, 1: 2606, 2: 3553, 3: 3929, ..........}

I want to classify the key, value pairs as binary - '1' or '0'. Below I represented

我想将键值对分类为二进制 - '1'或'0'。我代表的下面

for k, v in frequency_m.iteritems():
    if k ==0:
        print '0', v
    else:
        print '1', sum(v) 

obviously that generates TypeError: 'numpy.int64' object is not iterable. I am sure I need to iterate over the values and sum that up for the values other than '0'. I am not getting it. Any thoughts?

显然会生成TypeError:'numpy.int64'对象不可迭代。我确信我需要迭代这些值并将其与“0”以外的值相加。我没有得到它。有什么想法吗?

0 3512488
1 2606
1 3553
1 3929

my goal here is to output the table as

我的目标是输出表格

0 3512488
1 10088

I tried following as well: ** np.sum((value for key, value in frequency_m.iteritems() if key != '0'))**, it sums up all the values and does not yield my goal.

我也尝试过跟随:** np.sum((键的值,frequency_m.iteritems()中的值,如果键!='0'))**,它总结了所有的值并且不会产生我的目标。

1 个解决方案

#1

Just change your comprehension to check for 0 instead of '0':

只需改变你的理解力来检查0而不是'0':

np.sum((value for key, value in frequency_m.iteritems() if key != 0))