PHP字符串函数chop()不提供所需的输出

The following code:

下面的代码:

<?php
    $str='Who are you?';
    echo chop($str,'you?').'<br>';
    echo chop($str,'are you?').'<br>';
?>

gives me the output:

给我输出:

Who are
Wh

Why the second output is

为什么第二个输出是

Wh

and not

而不是

who

2 个解决方案

#1

because:

因为:

(PHP 4, PHP 5, PHP 7)
chop — Alias of rtrim()

(PHP 4, PHP 5, PHP 7) rtrim()别名

and

和

(PHP 4, PHP 5, PHP 7)
rtrim — Strip whitespace (or other characters) from the end of a string

(PHP 4、PHP 5、PHP 7) rtrim——字符串末尾的空格(或其他字符)

string rtrim ( string $str [, string $character_mask ] )

字符串rtrim (string $str [， string $character_mask])

So... you're feeding a character mask.

所以…你在喂一个人物面具。

Given that, "o" is in that mask, so it gets trimmed out

假设"o"在蒙版中，所以它会被删除

#2

In your string you have specified a character_mask, this is what reference says:

在您的字符串中指定了一个characters _mask，引用如下:

character_mask: You can also specify the characters you want to strip, by means of the character_mask parameter. Simply list all characters that you want to be stripped. With .. you can specify a range of characters.

还可以通过characters _mask参数指定要剥离的字符。只需列出您想要删除的所有字符。与. .您可以指定字符的范围。

In your case, there's an 'o' in the mask, for this reason all 'o' in $str have been deleted.

在你的例子中，面具中有一个“o”，因为这个原因，$str中的所有“o”都被删除了。

#1