I have a long sequence of hex digits in a string, such as
我在字符串中有一长串十六进制数字,例如
000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44
000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44
only much longer, several kilobytes. Is there a builtin way to convert this to a bytes object in python 2.6/3?
只有更长,几千字节。有没有内置的方法将其转换为python 2.6 / 3中的字节对象?
5 个解决方案
#1
41
Works in Python 2.7 and higher including python3:
适用于Python 2.7及更高版本,包括python3:
result = bytearray.fromhex('deadbeef')
Note: There seems to be a bug with the bytearray.fromhex()
function in Python 2.6. The python.org documentation states that the function accepts a string as an argument, but when applied, the following error is thrown:
注意:Python 2.6中的bytearray.fromhex()函数似乎存在错误。 python.org文档声明该函数接受一个字符串作为参数,但是在应用时,会抛出以下错误:
>>> bytearray.fromhex('B9 01EF')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: fromhex() argument 1 must be unicode, not str`
#2
39
You can do this with the hex codec. ie:
您可以使用十六进制编解码器执行此操作。即:
>>> s='000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44'
>>> s.decode('hex')
'\x00\x00\x00\x00\x00\x00HB@\xfa\x06=\xe5\xd0\xb7D\xad\xbe\xd6:\x81\xfa\xea9\x00\x00\xc8B\x86@\xa4=P\x05\xbdD'
#3
38
result = bytes.fromhex(some_hex_string)
#5
-2
import binascii
binascii.b2a_hex(obj)
#1
41
Works in Python 2.7 and higher including python3:
适用于Python 2.7及更高版本,包括python3:
result = bytearray.fromhex('deadbeef')
Note: There seems to be a bug with the bytearray.fromhex()
function in Python 2.6. The python.org documentation states that the function accepts a string as an argument, but when applied, the following error is thrown:
注意:Python 2.6中的bytearray.fromhex()函数似乎存在错误。 python.org文档声明该函数接受一个字符串作为参数,但是在应用时,会抛出以下错误:
>>> bytearray.fromhex('B9 01EF')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: fromhex() argument 1 must be unicode, not str`
#2
39
You can do this with the hex codec. ie:
您可以使用十六进制编解码器执行此操作。即:
>>> s='000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44'
>>> s.decode('hex')
'\x00\x00\x00\x00\x00\x00HB@\xfa\x06=\xe5\xd0\xb7D\xad\xbe\xd6:\x81\xfa\xea9\x00\x00\xc8B\x86@\xa4=P\x05\xbdD'
#3
38
result = bytes.fromhex(some_hex_string)
#4
#5
-2
import binascii
binascii.b2a_hex(obj)