Is it possible to set a form's ForeignKey field's queryset so that it will take separate queryset's and output them in <optgroup>
's?
是否可以设置表单的ForeignKey字段的查询集,以便它将采用单独的查询集并在
Here is what I have:
这是我有的:
views.py
form = TemplateFormBasic(initial={'template': digest.template.id})
form.fields['template'].queryset = Template.objects.filter(Q(default=1) | Q(user=request.user)).order_by('name')
In my Template model, I have default Templates and User-created templates. I want them to be visibly separated in the <select>
box eg.
在我的模板模型中,我有默认模板和用户创建的模板。我希望它们在
<select>
<optgroup label="Default Templates">
<option>Default 1</option>
<option>Default 2</option>
</optgroup>
<optgroup label="User Templates">
<option>User Template 1</option>
<option>User Template 2</option>
</optgroup>
</select>
Can this be done?
可以这样做吗?
2 个解决方案
#1
10
I was able to figure it out using the example given on this blog
我能够使用此博客上给出的示例来解决这个问题
views.py
form.fields['template'].choices = templates_as_choices(request)
def templates_as_choices(request):
templates = []
default = []
user = []
for template in Template.objects.filter(default=1).order_by('name'):
default.append([template.id, template.name])
for template in Template.objects.filter(user=request.user).order_by('name'):
user.append([template.id, template.name])
templates.append(['Default Templates', default])
templates.append(['User Templates', user])
return templates
#2
4
I've done in the past by not using a foreign key on the form, but rather a charfield with choices.
我过去没有在表单上使用外键,而是选择了一个字段。
A CharField with choices support optgroups. You need to have the choices in this format:
具有选项的CharField支持optgroups。您需要以这种格式进行选择:
('Group 1',(('1','Yada'),('2','Yada'))), ('Group 2',(('3','Bepety'),('4','Bopity')))
('第1组',(('1','Yada'),('2','Yada'))),('第2组',(('3','Bepety'),('4' 'Bopity')))
Choices can also be a callable. So I created my own function that traverses the models and builds a tuple like the above.
选择也可以是可赎回的。所以我创建了自己的函数,遍历模型并构建如上所述的元组。
#1
10
I was able to figure it out using the example given on this blog
我能够使用此博客上给出的示例来解决这个问题
views.py
form.fields['template'].choices = templates_as_choices(request)
def templates_as_choices(request):
templates = []
default = []
user = []
for template in Template.objects.filter(default=1).order_by('name'):
default.append([template.id, template.name])
for template in Template.objects.filter(user=request.user).order_by('name'):
user.append([template.id, template.name])
templates.append(['Default Templates', default])
templates.append(['User Templates', user])
return templates
#2
4
I've done in the past by not using a foreign key on the form, but rather a charfield with choices.
我过去没有在表单上使用外键,而是选择了一个字段。
A CharField with choices support optgroups. You need to have the choices in this format:
具有选项的CharField支持optgroups。您需要以这种格式进行选择:
('Group 1',(('1','Yada'),('2','Yada'))), ('Group 2',(('3','Bepety'),('4','Bopity')))
('第1组',(('1','Yada'),('2','Yada'))),('第2组',(('3','Bepety'),('4' 'Bopity')))
Choices can also be a callable. So I created my own function that traverses the models and builds a tuple like the above.
选择也可以是可赎回的。所以我创建了自己的函数,遍历模型并构建如上所述的元组。