使用oracle提供的regexp_substr()函数,对将IPV4地址分成4段:
select
v.ip as ip_address,
regexp_substr(v.ip,'[^.]+',1,1) as A,
regexp_substr(v.ip,'[^.]+',1,2) as B,
regexp_substr(v.ip,'[^.]+',1,3) as C,
regexp_substr(v.ip,'[^.]+',1,4) as D
from (select '192.168.253.183' as ip from dual) v
结果如下:
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