Android List(集合)中的对象以某一个字段排序

时间:2021-02-17 15:32:33

在Android开发中,有时我们需要对一个对象的集合按照某一个字段进行排序,

  • Bean
public class Student {
private int studentId;
private String studentName;
private int age;
public Student(int studentId , String studentName, int age){
this.studentId=studentId;
this.studentName=studentName;
this.age=age;
}
public int getStudentId() {
return studentId;
}
public void setStudentId(int studentId) {
this.studentId = studentId;
}
public String getStudentName() {
return studentName;
}
public void setStudentName(String studentName) {
this.studentName = studentName;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}

}
  • 实现排序

    实现排序比较类 Comparator ,里面实现排序规则。

public class test {

/**
* @param args
*/

public static void main(String[] args) {
Student stu1 = new Student (1,"zhangsan",28);
Student stu2 = new Student (2,"zhagnsan",19);
Student stu3 = new Student (3,"wangwu",19);
Student stu4 = new Student (4,"wangwu",19);
Student stu5 = new Student (5,"zhaoliu",18);

ArrayList<Student> list = new ArrayList<Student>();
list.add(stu1);
list.add(stu2);
list.add(stu3);
list.add(stu4);
list.add(stu5);
//排序规则,这里是以年龄先排序,如果年龄相同
Comparator<Student> comparator = new Comparator<Student>() {
public int compare(Student s1, Student s2) {
// 先排年龄
if (s1.getAge() != s2.getAge()) {
return s1.getAge() - s2.getAge();
} else if (!s1.getStudentName().equals(s2.getStudentName())) {
// 年龄相同则按姓名排序
return s1.getStudentName().compareTo(s2.getStudentName());
} else {
// 姓名也相同则按学号排序
return s1.getStudentId() - s2.getStudentId();
}
}
};

//这里就会自动根据规则进行排序
Collections.sort(list,comparator);
for(int i=0;i<list.size();i++){
Student stu=list.get(i);
System.out.println("年龄:"+stu.getAge()+" 姓名:"+stu.getStudentName()+" 学号:"+stu.getStudentId());
}

}

}

排序结果

结果:
年龄:18 姓名:zhaoliu 学号:5
年龄:19 姓名:wangwu 学号:3
年龄:19 姓名:wangwu 学号:4
年龄:19 姓名:zhagnsan 学号:2
年龄:28 姓名:zhangsan 学号:1

也可以想下面这样写:

    Collections.sort(list, new Comparator<GoodsBean>() {
@Override
public int compare(GoodsBean bean1, GoodsBean bean2) {

if (Integer.valueOf(bean1.getScore()).compareTo(Integer.valueOf(bean2.getScore())) == 0) {
return Integer.valueOf(bean1.getRecommend_num()).compareTo(Integer.valueOf(bean2.getRecommend_num()));
} else {
return Integer.valueOf(bean1.getScore()).compareTo(Integer.valueOf(bean2.getScore()));
}
}
});

这样就可以对一个集合中的数据各种排序了。