整数扩展- 1、2、3等[重复]

Possible Duplicate:
NSNumberFormatter and ‘th’ ‘st’ ‘nd’ ‘rd’ (ordinal) number endings

可能的重复:NSNumberFormatter和th ' st ' nd ' rd '(序号)数字结尾

Hello,

你好,

I'm building an application that downloads player ranks and displays them. So say for example, you're 3rd out of all the players, I inserted a condition that will display it as 3rd, not 3th and i did the same for 2nd and 1st. When getting to higher ranks though, such as 2883rd, it'll display 2883th (for obvious reasons)

我正在构建一个应用程序，下载玩家的等级并显示它们。举个例子，你在所有玩家中排名第三，我插入了一个条件将它显示为第3，而不是第3我在第2和第1做了同样的事情。但是，当级别更高时，比如2883，它将显示2883

My question is, how can I get it to reformat the number to XXX1st, XXX2nd, XXX3rd etc?

我的问题是，如何将数字重新格式化为xxx1、xxx2、xxx3等等?

To show what I mean, here's how I format my number to add a "rd" if it's 3

为了显示我的意思，这里是我如何格式化我的数字来添加一个“rd”，如果它是3。

if ([[container stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]] isEqualToString:@"3"])
{
    NSString*badge = [NSString stringWithFormat:@"%@rd",[container stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]]];
    NSString*scoreText = [NSString stringWithFormat:@"ROC Server Rank: %@rd",[container stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]]];
    profile.badgeValue = badge;
    rank.text = scoreText;
}

I can't do this for every number up to 2000 (there are 2000 ranks in total) - what can I do to solve this problem?

我不能对2000年前的每一个数字都这样做(总共有2000个等级)——我能做什么来解决这个问题?

2 个解决方案

#1

Make it check the last digit of every number then add the suffix accordingly.

让它检查每个数字的最后一个数字，然后添加相应的后缀。

Checking the last 2 digits will fix it.

检查最后两位数就可以了。

#2

Here's a short snippet in another language: http://www.bytechaser.com/en/functions/b6yhfyxh78/convert-number-to-ordinal-like-1st-2nd-in-c-sharp.aspx

下面是另一种语言的一个简短片段:http://www.bytechaser.com/en/functions/b6yhfyxh78/convert- to-ordinal-like-1st-2nd-in- sharp.aspx

/// <summary>
/// Create an ordinal number from any number 
/// e.g. 1 becomes 1st and 22 becomes 22nd
/// </summary>
/// <param name="number">Number to convert</param>
/// <returns>Ordinal value as string</returns>
public static string FormatOrdinalNumber(int number)
{
    //0 remains just 0
    if (number == 0) return "0";
    //test for number between 3 and 21 as they follow a 
    //slightly different rule and all end with th            
    if (number > 3 && number < 21)
    {
        return number + "th";
    }
    //return the last digit of the number e.g. 102 is 2
    var lastdigit = number % 10;
    //append the correct ordinal val
    switch (lastdigit)
    {
        case 1: return number + "st";
        case 2: return number + "nd";
        case 3: return number + "rd";
        default: return number + "th";
    }
}

#1