其中Master.MasterId和Brand.BrandName是主外键关系
MasterId MasterName BrandName
1 中国移动 全球通
1 中国移动 动感地带
1 中国移动 神州行
现在我想显示为如下格式:
MasterId MasterName BrandName
1 中国移动 全球通、动感地带、神州行
有没有一条Sql可以实现的?数据库是Oracle10g,谢谢大家~
如果不能用Sql语句,其他方法如何实现呢?
9 个解决方案
#1
为何不去Oracle区发帖?
#2
建议去ORACLE问问
#3
MS-SQL的:
合并列值
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加)
1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb
/*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(2 行受影响)
*/
--SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id
/*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc
(2 row(s) affected)
*/
drop table tb
#4
MSSQL里可以通过:
select MasterID,MasterName,stuff((select ','+BrandName from 连接表
where MasterID=a.MasterID for xml path('')),1,1,'') from 连接表 a group by MasterID,MasterName
来实现.
select MasterID,MasterName,stuff((select ','+BrandName from 连接表
where MasterID=a.MasterID for xml path('')),1,1,'') from 连接表 a group by MasterID,MasterName
来实现.
#5
select masterid,mastername, [brandName]=stuff((select ','+[brandName] from tb t where masterid=tb.masterid
for xml path('')), 1, 1, '')
from tb
group by masterid ,mastername
#6
select MasterID,MasterName,replace(wm_concat(BrandName),',',';') class from temp group by MasterID,MasterName
试一下,temp为二个表的集合
试一下,temp为二个表的集合
#7
谢谢大家的回答,明天到公司后验证后散分~
#8
select MasterID,MasterName,wm_concat(BrandName) class
from temp group by MasterID,MasterName
from temp group by MasterID,MasterName
#9
回3#,4#,Oracle没有STUFF函数吧?
#1
为何不去Oracle区发帖?
#2
建议去ORACLE问问
#3
MS-SQL的:
合并列值
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加)
1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb
/*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(2 行受影响)
*/
--SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id
/*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc
(2 row(s) affected)
*/
drop table tb
#4
MSSQL里可以通过:
select MasterID,MasterName,stuff((select ','+BrandName from 连接表
where MasterID=a.MasterID for xml path('')),1,1,'') from 连接表 a group by MasterID,MasterName
来实现.
select MasterID,MasterName,stuff((select ','+BrandName from 连接表
where MasterID=a.MasterID for xml path('')),1,1,'') from 连接表 a group by MasterID,MasterName
来实现.
#5
select masterid,mastername, [brandName]=stuff((select ','+[brandName] from tb t where masterid=tb.masterid
for xml path('')), 1, 1, '')
from tb
group by masterid ,mastername
#6
select MasterID,MasterName,replace(wm_concat(BrandName),',',';') class from temp group by MasterID,MasterName
试一下,temp为二个表的集合
试一下,temp为二个表的集合
#7
谢谢大家的回答,明天到公司后验证后散分~
#8
select MasterID,MasterName,wm_concat(BrandName) class
from temp group by MasterID,MasterName
from temp group by MasterID,MasterName
#9
回3#,4#,Oracle没有STUFF函数吧?