Below code works well and it labels the barplot correctly, However, If I try geom_text for a histogram I Fail since geom_text requires a y-component and a histogram's y component is the frequency which is never a part of the code then HOW DO I bring labels for a Histogram?
下面的代码工作得很好，它正确地标记了条形图，但是，如果我尝试使用geom_text来表示我失败的直方图，因为geom_text需要一个y分量，而一个直方图的y分量是频率，这不是代码的一部分，那么我如何为直方图添加标签呢?
Works Well
工作得很好
ggplot(csub, aes(x=Year, y=Anomaly10y, fill=pos)) +
geom_bar(stat="identity", position="identity") +
geom_text(aes(label=Anomaly10y,vjust=1.5))
Problem- no Y component(indicated by ?) in the below code for geom_text
问题-在geom_text的下面代码中没有Y组件(由?表示)
ggplot(csub,aes(x=Anomaly10y)) +
geom_histogram()
geom_text(aes(label=?,vjust=1.5))
By Default geom requires x and y component,
默认情况下，geom需要x和y分量，
What should I do when I dont have y-component as it is automatically generated by the function?
当我没有y分量时该怎么办，因为它是由函数自动生成的?
1 个解决方案
#1
32
geom_histogram() is just a fancy wrapper to stat_bin so you can all that yourself with the bars and text that you like. Here's an example
geom_histogram()只是stat_bin的一个漂亮的包装，因此您可以自己使用喜欢的条形和文本。这里有一个例子
#sample data
set.seed(15)
csub<-data.frame(Anomaly10y = rpois(50,5))
And then we plot it with
然后画出来
ggplot(csub,aes(x=Anomaly10y)) +
stat_bin(binwidth=1) + ylim(c(0, 12)) +
stat_bin(binwidth=1, geom="text", aes(label=..count..), vjust=-1.5)
to get
得到
#1
32
geom_histogram() is just a fancy wrapper to stat_bin so you can all that yourself with the bars and text that you like. Here's an example
geom_histogram()只是stat_bin的一个漂亮的包装，因此您可以自己使用喜欢的条形和文本。这里有一个例子
#sample data
set.seed(15)
csub<-data.frame(Anomaly10y = rpois(50,5))
And then we plot it with
然后画出来
ggplot(csub,aes(x=Anomaly10y)) +
stat_bin(binwidth=1) + ylim(c(0, 12)) +
stat_bin(binwidth=1, geom="text", aes(label=..count..), vjust=-1.5)
to get
得到