Your Ride Is Here
It is a well-known fact that behind every good comet is a UFO. These UFOs often come to collect loyal supporters from here on Earth. Unfortunately, they only have room to pick up one group of followers on each trip. They do, however, let the groups know ahead of time which will be picked up for each comet by a clever scheme: they pick a name for the comet which, along with the name of the group, can be used to determine if it is a particular group's turn to go (who do you think names the comets?). The details of the matching scheme are given below; your job is to write a program which takes the names of a group and a comet and then determines whether the group should go with the UFO behind that comet.
Both the name of the group and the name of the comet are converted into a number in the following manner: the final number is just the product of all the letters in the name, where "A" is 1 and "Z" is 26. For instance, the group "USACO" would be 21 * 19 * 1 * 3 * 15 = 17955. If the group's number mod 47 is the same as the comet's number mod 47, then you need to tell the group to get ready! (Remember that "a mod b" is the remainder left over after dividing a by b; 34 mod 10 is 4.)
Write a program which reads in the name of the comet and the name of the group and figures out whether according to the above scheme the names are a match, printing "GO" if they match and "STAY" if not. The names of the groups and the comets will be a string of capital letters with no spaces or punctuation, up to 6 characters long.
Examples:
| Input | Output |
COMETQ HVNGAT |
GO |
ABSTAR USACO |
STAY |
PROGRAM NAME: ride
This means that you fill in your header with:PROG: ride
WARNING: You must have 'ride' in this field or the wrong test data (or no test data) will be used.
INPUT FORMAT
| Line 1: | An upper case character string of length 1..6 that is the name of the comet. |
| Line 2: | An upper case character string of length 1..6 that is the name of the group. |
NOTE: The input file has a newline at the end of each line but does not have a "return". Sometimes, programmers code for the Windows paradigm of "return" followed by "newline"; don't do that! Use simple input routines like "readln" (for Pascal) and, for C/C++, "fscanf" and "fid>>string".
NOTE 2: Because of the extra characters, be sure to leave enough room for a 'newline' (also notated as '\n') and an end of string character ('\0') if your language uses it (as C and C++ do). This means you need eight characters of room instead of six.
SAMPLE INPUT (file ride.in)
COMETQ HVNGAT
OUTPUT FORMAT
A single line containing either the word "GO" or the word "STAY".SAMPLE OUTPUT (file ride.out)
GO
OUTPUT EXPLANATION
Converting the letters to numbers:| C | O | M | E | T | Q | |
| 3 | 15 | 13 | 5 | 20 | 17 | |
| H | V | N | G | A | T | |
| 8 | 22 | 14 | 7 | 1 | 20 |
3 * 15 * 13 * 5 * 20 * 17 = 994500 mod 47 = 27 8 * 22 * 14 * 7 * 1 * 20 = 344960 mod 47 = 27
Because both products evaluate to 27 (when modded by 47), the mission is 'GO'.
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我靠，才第一题就懵逼了，因为这个USACO和我之前遇到的OJ都不一样，它这个没有标准输入输出，只能按文件输入输出，关于C++的文件输入输出，我找到了一个很好的文章http://wenku.baidu.com/link?url=UdXYKPHzoCYsJ7LlbQyBLU0W16rnXUrjEgwDb9qeIjJHyQsHSsM9Kfbs2zh4807QISxrrcznhHDAAXLv9cB7HLLqlXDyiSGBP4U2Z6l2vUy
有二十多页，对我这种笨人来说不太容易一次性全部搞明白，只能一次一次慢慢熟练。
就这道题来说，主要是学习了这么几个方面，对于文件输入输出，需要用到#include<fstream>,这时候就不需要iostream了，因为平常用的cin，cout这些都在fstream里面。
打开一个文件准备向里面输出结果是写成 ofstream fout（"file name"），打开文件准备读取是 ifstream fin("file name")，
其中fout，fin这些是可以自己定义的。
还有一点就是string类型的字符串，其大小应该是变量名.size()，反正貌似不能用strlen（）233333333，不是很懂怎么写一份好的题解，就这样吧
/*
ID: obamarx1
PROG: ride
LANG: C++
*/
#include<iostream>
#include<cstring>
#include<fstream>
using namespace std;
int main(){
string a,b;
ofstream fout("ride.out");
ifstream fin("ride.in");
while(fin>>a>>b){
int i,len1=a.size(),len2=b.size();
int sum1=1,sum2=1;
for(i=0;i<len1;i++){
int temp=(int)(a[i]-'A')+1;
sum1*=temp;
}
for(i=0;i<len2;i++){
int temp=(int)(b[i]-'A')+1;
sum2*=temp;
}
if(sum1%47==sum2%47){
fout<<"GO\n";
}else {
fout<<"STAY\n";
}
}
return 0;
}