使用具有相同类的子和父div的beautifulSoup解析HTML

I have this HTML from which I have to extract data:

我有这个HTML，我必须从中提取数据：

<html>
<head></head>
<body>
<div class="main">
  <div class="utlimate"><p>hello</p></div>
  <div class = "headline"><p>some text</p></div>
   <div class="content">
     <div class = "utimate"> <p>TOP</p>
        <div class ="utlimate"> <p>data1</p></div>
        <div class ="utlimate"> <p>it could be anything</p></div>
        <div class ="utlimate"> <p>not</p></div>
        <div class ="utlimate"> <p></p></div>

     </div>
   </div>
</div>
</body>
</html>

I need to access <div class="ultimate"> with <p> that has value "data1", "it could be anything", "not".The code I tried for this :

我需要使用

来访问

，其值为“data1”，“它可能是任何东西”，“不是”。我为此尝试的代码：

soup = BeautifulSoup(HTML_data)     #HTML_data is all html content
first_div = soup.find('div',{"class" : "content"})
second_div = first_div.find('div',{"class" : "utlimate"})
div_list = second_div.findall('div',{"class" : "utlimate"})

I got error in my code last line 'NoneType' object is not callable

我的代码最后一行出现错误'NoneType'对象不可调用

How do i access only those div's???plz help

我如何只访问那些div的??? plz帮助

2 个解决方案

#1

Try this:

尝试这个：

soup = BeautifulSoup(HTML_data)     #HTML_data is all html content
first_div = soup.find('div',{"class" : "content"})
second_div = first_div.find('div',{"class" : "utimate"})
div_list = second_div.findAll('div',{"class" : "utlimate"})

The method for getting the list is findAll, not findall. There's no "ultimate" in the HTML fragment, they're "utlimate" or "utimate". Are those typos?

获取列表的方法是findAll，而不是findall。 HTML片段中没有“终极”，它们“非常”或“非常”。这些错别字吗？

#2

Is Soup None?

汤没有？

I suggest you re-factor your code to guard against this:

我建议你重新考虑你的代码以防止这种情况：

soup = BeautifulSoup(HTML_data)     #HTML_data is all html content
if soup ==None:
    //Error
else:
    c = soup.contents
    // Use RE here

#1