如何在php中比较两个日期

How to compare two dates in php if dates are in format '03_01_12' and '31_12_11' .

如果日期是“03_01_12”和“31_12_11”格式，如何在php中比较两个日期。

I am using this code:

我使用的代码是:

$date1=date('d_m_y');
$date2='31_12_11';
if(strtotime($date1) < strtotime($date2))
   echo '1 is small ='.strtotime($date1).','.$date1;
else
   echo '2 is small ='.strtotime($date2).','.$date2;

But its not working..

但它不工作。

13 个解决方案

#1

You will have to make sure that your dates are valid date objects.

您必须确保您的日期是有效的日期对象。

Try this:

试试这个:

$date1=date('d/m/y');
$tempArr=explode('_', '31_12_11');
$date2 = date("d/m/y", mktime(0, 0, 0, $tempArr[1], $tempArr[0], $tempArr[2]));

You can then perform the strtotime() method to get the difference.

然后，您可以执行strtotime()方法来获得差异。

#2

105

Your brackets are not all matched:

您的括号并非都匹配:

if(strtotime($date1))<strtotime($date2)))

Change to this:

改变:

if(strtotime($date1) < strtotime($date2))

#3

Using DateTime::createFromFormat:

使用DateTime::createFromFormat:

$format = "d_m_y";
$date1  = \DateTime::createFromFormat($format, "03_01_12");
$date2  = \DateTime::createFromFormat($format, "31_12_11");

var_dump($date1 > $date2);

#4

The date_diff() function returns the difference between two DateTime objects.

函数的作用是:返回两个DateTime对象之间的差值。

If the first date is before the second date a positive number of days will be returned; otherwise a negative number of days:

如果第一个日期是在第二个日期之前，则返回一个正数天数;否则天数为负数:

<?php
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
?>

output will be "+272 days" ;

输出为“+272天”;

changing $date1 = "2014-03-15"

改变美元date1 = " 2014-03-15 "

 <?php
    $date1=date_create("2014-03-15");
    $date2=date_create("2013-12-12");
    $diff=date_diff($date1,$date2);
    echo $diff->format("%R%a days");
    ?>

Output will be "-93 days"

输出将是“-93天”

#5

Extending @nevermind's answer, one can use DateTime::createFromFormat: like,

扩展@nevermind的答案，可以使用DateTime::createFromFormat: like，

// use - instead of _. replace _ by - if needed.
$format = "d-m-y";
$date1  = DateTime::createFromFormat($format, date('d-m-y'));
$date2  = DateTime::createFromFormat($format, str_replace("_", "-",$date2));    
var_dump($date1 > $date2);

#6

<?php
       $expiry_date = "2017-12-31 00:00:00"
       $today = date('d-m-Y',time()); 
       $exp = date('d-m-Y',strtotime($expiry_date));
       $expDate =  date_create($exp);
       $todayDate = date_create($today);
       $diff =  date_diff($todayDate, $expDate);
       if($diff->format("%R%a")>0){
             echo "active";
       }else{
           echo "inactive";
       }
       echo "Remaining Days ".$diff->format("%R%a days");
?>

#7

you can try something like:

你可以试试:

        $date1 = date_create('2014-1-23'); // format of yyyy-mm-dd
        $date2 = date_create('2014-2-3'); // format of yyyy-mm-dd
        $dateDiff = date_diff($date1, $date2);
        var_dump($dateDiff);

You can then access the difference in days like this $dateDiff->d;

然后您可以访问不同的天，如$dateDiff->d;

#8

Don't know what you're problem is but:

不知道你的问题是什么，但是:

function date_compare($d1, $d2)
{
    $d1 = explode('_', $d1);
    $d2 = explode('_', $d2);

    $d1 = array_reverse($d1);
    $d2 = array_reverse($d2);

    if (strtotime(implode('-', $d1)) > strtotime(implode('-', $d2)))
    {
        return $d2;
    }
    else
    {
        return $d1;
    }
}

#9

Try this

试试这个

$data1 = strtotime(\date("d/m/Y"));
$data1 = date_create($data1);
$data2 = date_create("21/06/2017");

if($data1 < $data2){
    return "The most current date is date1";
}

return "The most current date is date2";

#10

compare the result of maketime() for each of the time

比较maketime()的结果

#11

I know this is late, but for future reference, put the date format into a recognised format by using str_replace then your function will work. (replace the underscore with a dash)

我知道这已经很晚了，但是为了以后的参考，请使用str_replace将日期格式转换为可识别的格式，这样您的函数就可以工作了。(用破折号替换下划线)

//change the format to dashes instead of underscores, then get the timestamp
$date1 = strtotime(str_replace("_", "-",$date1));
$date2 = strtotime(str_replace("_", "-",$date2));

//compare the dates
if($date1 < $date2){
   //convert the date back to underscore format if needed when printing it out.
   echo '1 is small='.$date1.','.date('d_m_y',$date1);
}else{
   echo '2 is small='.$date2.','.date('d_m_y',$date2);
}

#12

You can to converte for integer number and compare.

可以对整数进行收敛并进行比较。

Eg.:

如:

$date_1 = date('Ymd'); $date_2 = '31_12_2011';

$ date_1 =日期(“Ymd”);美元date_2 = 31 _12_2011”;

$date_2 = (int) implode(array_reverse(explode("_", $date_2)));

美元date_2 =(int)内爆(array_reverse(爆炸(“_”,date_2美元)));

echo ($date_1 < $date_2) ? '$date_2 is bigger then $date_1' : '$date_2 is smaller than $date_1';

echo ($date_1 < $date_2) ?“$date_2大于$date_1”:“$date_2小于$date_1”;

#13

Not answering the OPs actual problem, but answering just the title. Since this is the top result for "comparing dates in php".

没有回答OPs的实际问题，只是回答了标题。因为这是“在php中比较日期”的最高结果。

Pretty simple to use Datetime Objects (v>= 5.3.0) and Compare them directly

使用Datetime对象非常简单(v>= 5.3.0)，并直接比较它们。

$date1 = new DateTime("now");
$date2 = new DateTime("tomorrow");
var_dump($date1 < $date2);

Note: Datetime object can also be created for a predefined date as below.

注意:Datetime对象也可以创建为预定义的日期，如下所示。

$date1 = new DateTime('2009-10-11');

#1