I have two tables.
我有两个表。
One of them called "conversations" has the following data.
其中一个叫做“对话”的数据如下。
ConversationID Sender Reciever
1 bla1 bla2
2 bla1 bla3
3 bla1 bla4
The other is called "Messages" has the following data.
另一种叫做“消息”,有以下数据。
MessageID MessageText TimeAddedMessage ConversationID
1 helo 2012-03-12 13:00:00 2
2 helo 2012-03-12 13:01:00 1
3 helo 2012-03-12 13:02:00 3
4 helo 2012-03-12 13:03:00 3
5 helo 2012-03-12 13:04:00 2
The result i want from the query is the following:
我想从查询中得到的结果如下:
5 helo 2012-03-12 13:04:00 2
4 helo 2012-03-12 13:03:00 3
2 helo 2012-03-12 13:01:00 1
Which means that we need the most recent comment for each conversation (sorted DESC by time).
这意味着我们需要每个对话的最新评论(按时间排序DESC)。
Any help appreciated.
任何帮助表示赞赏。
3 个解决方案
#1
3
Try -
试一试,
SELECT m2.*, c.Sender
FROM (
SELECT m1.ConversationID, MAX(m1.MessageID) AS MessageID
FROM Messages m1
GROUP BY m1.ConversationID
) latest_msg
INNER JOIN Messages m2
ON latest_msg.MessageID = m2.MessageID
AND latest_msg.ConversationID = m2.ConversationID
INNER JOIN Conversations c
ON m2.ConversationID = c.ConversationID
ORDER BY m2.MessageID DESC
EDIT I have modified the above query to include the value of Sender from the Conversations table. I have noticed that your structure for the conversation is a bit odd. A conversation is FROM one user TO another user but there is no way to identify which user wrote each message. Is this intentional?
我已经修改了上面的查询,以包含来自对话表的Sender的值。我注意到你谈话的结构有点奇怪。对话是从一个用户到另一个用户,但是无法确定每个消息是哪个用户写的。这是故意的吗?
#2
1
You can do it by creating derived table with ConversationID and max TimeAddedMessage and joining it back to Messages:
您可以通过使用ConversationID和max TimeAddedMessage创建派生表并将其连接到消息中来实现:
select Messages.MessageID, Messages.MessageText,
Messages.TimeAddedMessage, Messages.ConversationID
from Messages inner join
(
select ConversationID, max (TimeAddedMessage) TimeAddedMessage
from Messages
group by ConversationID
) LastMessages
on Messages.ConversationID = LastMessages.ConversationID
and Messages.TimeAddedMessage = LastMessages.TimeAddedMessage
#3
1
A simple query with good performance for comparitively small datasets.
一个简单的查询,具有比较小的数据集的良好性能。
SELECT m1.*
FROM Messages m1 LEFT JOIN Messages m2
ON (m1.ConversationId = m2.ConversationId AND m1.TimeAddedMessage < m2.TimeAddedMessage)
WHERE m2.MessageID IS NULL;
Modified from this post.
从这篇文章修改。
It's kind of counter intuitive but has become somewhat of an often used cookbook recipe.
这是一种反直觉的做法,但已经成为了一种常用的食谱食谱。
#1
3
Try -
试一试,
SELECT m2.*, c.Sender
FROM (
SELECT m1.ConversationID, MAX(m1.MessageID) AS MessageID
FROM Messages m1
GROUP BY m1.ConversationID
) latest_msg
INNER JOIN Messages m2
ON latest_msg.MessageID = m2.MessageID
AND latest_msg.ConversationID = m2.ConversationID
INNER JOIN Conversations c
ON m2.ConversationID = c.ConversationID
ORDER BY m2.MessageID DESC
EDIT I have modified the above query to include the value of Sender from the Conversations table. I have noticed that your structure for the conversation is a bit odd. A conversation is FROM one user TO another user but there is no way to identify which user wrote each message. Is this intentional?
我已经修改了上面的查询,以包含来自对话表的Sender的值。我注意到你谈话的结构有点奇怪。对话是从一个用户到另一个用户,但是无法确定每个消息是哪个用户写的。这是故意的吗?
#2
1
You can do it by creating derived table with ConversationID and max TimeAddedMessage and joining it back to Messages:
您可以通过使用ConversationID和max TimeAddedMessage创建派生表并将其连接到消息中来实现:
select Messages.MessageID, Messages.MessageText,
Messages.TimeAddedMessage, Messages.ConversationID
from Messages inner join
(
select ConversationID, max (TimeAddedMessage) TimeAddedMessage
from Messages
group by ConversationID
) LastMessages
on Messages.ConversationID = LastMessages.ConversationID
and Messages.TimeAddedMessage = LastMessages.TimeAddedMessage
#3
1
A simple query with good performance for comparitively small datasets.
一个简单的查询,具有比较小的数据集的良好性能。
SELECT m1.*
FROM Messages m1 LEFT JOIN Messages m2
ON (m1.ConversationId = m2.ConversationId AND m1.TimeAddedMessage < m2.TimeAddedMessage)
WHERE m2.MessageID IS NULL;
Modified from this post.
从这篇文章修改。
It's kind of counter intuitive but has become somewhat of an often used cookbook recipe.
这是一种反直觉的做法,但已经成为了一种常用的食谱食谱。