However above [duplicate suggestion] is for multidimensional array, not targeting the simpler case I am posing here.
但是上面的[重复建议]是多维数组，而不是针对我在这里提出的更简单的情况。
For example if I have:
例如，如果我有：
'one','two','three','four','five'
I want to select three as it is the longest string. I tried:
我想选择三个，因为它是最长的字符串。我试过了：
['one','two','three','four','five'].select{|char_num| char_num.size.max}
but Enumerable#max doesn't return the right result.
但是Enumerable #max不会返回正确的结果。
3 个解决方案
#1
43
Just do as below using Enumerable#max_by :
使用Enumerable＃max_by执行以下操作：
ar = ['one','two','three','four','five']
ar.max_by(&:length) # => "three"
#2
1
arr.map(&:length).max -
#3
0
You can also use:
您还可以使用：
['one','two','three','four','five'].inject { |f, s| f.length > s.length ? f : s }
#1
43
Just do as below using Enumerable#max_by :
使用Enumerable＃max_by执行以下操作：
ar = ['one','two','three','four','five']
ar.max_by(&:length) # => "three"
#2
1
arr.map(&:length).max -
#3
0
You can also use:
您还可以使用：
['one','two','three','four','five'].inject { |f, s| f.length > s.length ? f : s }