If I have two std::functions, how can I check whether both hold the same function or not?
如果我有两个std:::函数，如何检查两个函数是否都包含相同的函数?
Additional Information: I have a vector of functions std::vector<std::function<void()>> and before adding another function to the vector I want to check if it already is contained.
附加信息:我有一个函数向量std::向量
<::>
>，在向向量添加另一个函数之前，我想检查它是否已经包含。
函数
2 个解决方案
#1
4
I dont think that they both can be compared. Here is an example to explain some points on std::function comparison
我不认为两者可以相提并论。这里有一个例子来解释std:::函数比较
#2
-1
Generally std::function and boost::function are not comparable because they need their stored object be comparable but not all function objects and also lambdas have operator== so std or boost functions have no way to compare them
一般来说，std::function和boost:::function是不可比较的，因为它们需要存储的对象是可比较的，但不是所有的函数对象，而且lambdas有操作符==，所以std或boost函数没有办法对它们进行比较
#1
4
I dont think that they both can be compared. Here is an example to explain some points on std::function comparison
我不认为两者可以相提并论。这里有一个例子来解释std:::函数比较
#2
-1
Generally std::function and boost::function are not comparable because they need their stored object be comparable but not all function objects and also lambdas have operator== so std or boost functions have no way to compare them
一般来说，std::function和boost:::function是不可比较的，因为它们需要存储的对象是可比较的，但不是所有的函数对象，而且lambdas有操作符==，所以std或boost函数没有办法对它们进行比较