Say I have the following code:
假设我有以下代码:
def func(a,b):
return (func2(a),func3(3))
def paralel_func(alist,blist)
with ThreadPoolExecutor(max_workers=None) as executor:
executor.map(func,alist,blist)
How do I access the return values that were returned from func
? I tried to figure it out myself by thinking that executor.map
is a list that holds the values but that didnt work for me.
如何访问从func返回的返回值?我试着通过考虑遗嘱执行人来弄清楚。map是一个包含值的列表,但对我来说并不适用。
1 个解决方案
#1
2
May be you should try this
也许你应该试试这个
ablists = [alist, blist]
with concurrent.futures.ThreadPoolExecutor(max_workers=3) as executor:
future_list= {executor.submit(func, a, b): i for i in ablists}
You can read more here about futures and also executors
你可以在这里读到更多关于期货和执行者的信息
#1
2
May be you should try this
也许你应该试试这个
ablists = [alist, blist]
with concurrent.futures.ThreadPoolExecutor(max_workers=3) as executor:
future_list= {executor.submit(func, a, b): i for i in ablists}
You can read more here about futures and also executors
你可以在这里读到更多关于期货和执行者的信息