I'm trying to store info to a mysql database, but for some reason it's not working for me.
我正在尝试将信息存储到mysql数据库,但由于某种原因它不适合我。
Dim connString As String = "server=sql3.freemysqlhosting.net; userid=Censored;password=Censored;database=sql364455"
Dim conn As New MySqlConnection(connString)
Dim cmd As New MySqlCommand()
Try
conn.Open()
cmd.Connection = conn
cmd.CommandText = "INSERT INTO accounts (`user_num`, `username`, `password`) values (@1,@2,@3)"
MsgBox("1")
cmd.Parameters.AddWithValue("@1", TextBox1.Text)
cmd.Parameters.AddWithValue("@2", TextBox2.Text)
cmd.Parameters.AddWithValue("@3", TextBox3.Text)
MsgBox("2")
cmd.ExecuteNonQuery()
MsgBox("3")
MessageBox.Show("User Profile Created!", "Success!", MessageBoxButtons.OK, MessageBoxIcon.Asterisk)
conn.Close()
Catch ex As Exception
End Try
According to this code the message boxes 1 and 2 is popping up but 3 is not.
根据此代码,消息框1和2弹出,但3不弹出。
Any idea? thanks in advance.
任何想法?提前致谢。
1 个解决方案
#1
0
@WoeIsMe Plutonix already told you how to write it correctly (put it into brackets: [password]). And, just and advice; if you're already using MsgBox as a debugging tool, always put another one inside the catch block with the exception MsgBox(ex.ToString()), so you'll know why it is not working. – Josh Part 8
@WoeIsMe Plutonix已经告诉你如何正确编写它(把它放在括号中:[密码])。而且,只是和建议;如果您已经使用MsgBox作为调试工具,请始终将另一个放在catch块中,并使用MsgBox(ex.ToString()),因此您将知道它为什么不起作用。 - Josh Part 8
I've put a msgbox on the exception block to find out what is the problem and I found that it didn't worked because: "Duplicate entry '0' for key 'PRIMARY' " - it didn't worked because there was already a user with this number.
我在异常块上放了一个msgbox来找出问题是什么,我发现它没有用,因为:“重复条目'0'用于键'PRIMARY'” - 它没有用,因为已经有了拥有此号码的用户。
thanks alot for all the people who helped me.
非常感谢所有帮助过我的人。
the code I used to detect the problem:
我用来检测问题的代码:
Dim connString As String = "server=sql3.freemysqlhosting.net; userid=username;password=password;database=sql364455"
Dim conn As New MySqlConnection(connString)
Dim cmd As New MySqlCommand()
Try
conn.Open()
cmd.Connection = conn
cmd.CommandText = "INSERT INTO accounts (user_num, username, password) values (@1,@2,@3)"
MsgBox("1")
cmd.Parameters.AddWithValue("@1", TextBox1.Text)
cmd.Parameters.AddWithValue("@2", TextBox2.Text)
cmd.Parameters.AddWithValue("@3", TextBox3.Text)
MsgBox("2")
cmd.ExecuteNonQuery()
MsgBox("3")
MessageBox.Show("User Profile Created!", "Success!", MessageBoxButtons.OK, MessageBoxIcon.Asterisk)
conn.Close()
Catch ex As Exception
' here
MsgBox(ex.Message)
End Try
#1
0
@WoeIsMe Plutonix already told you how to write it correctly (put it into brackets: [password]). And, just and advice; if you're already using MsgBox as a debugging tool, always put another one inside the catch block with the exception MsgBox(ex.ToString()), so you'll know why it is not working. – Josh Part 8
@WoeIsMe Plutonix已经告诉你如何正确编写它(把它放在括号中:[密码])。而且,只是和建议;如果您已经使用MsgBox作为调试工具,请始终将另一个放在catch块中,并使用MsgBox(ex.ToString()),因此您将知道它为什么不起作用。 - Josh Part 8
I've put a msgbox on the exception block to find out what is the problem and I found that it didn't worked because: "Duplicate entry '0' for key 'PRIMARY' " - it didn't worked because there was already a user with this number.
我在异常块上放了一个msgbox来找出问题是什么,我发现它没有用,因为:“重复条目'0'用于键'PRIMARY'” - 它没有用,因为已经有了拥有此号码的用户。
thanks alot for all the people who helped me.
非常感谢所有帮助过我的人。
the code I used to detect the problem:
我用来检测问题的代码:
Dim connString As String = "server=sql3.freemysqlhosting.net; userid=username;password=password;database=sql364455"
Dim conn As New MySqlConnection(connString)
Dim cmd As New MySqlCommand()
Try
conn.Open()
cmd.Connection = conn
cmd.CommandText = "INSERT INTO accounts (user_num, username, password) values (@1,@2,@3)"
MsgBox("1")
cmd.Parameters.AddWithValue("@1", TextBox1.Text)
cmd.Parameters.AddWithValue("@2", TextBox2.Text)
cmd.Parameters.AddWithValue("@3", TextBox3.Text)
MsgBox("2")
cmd.ExecuteNonQuery()
MsgBox("3")
MessageBox.Show("User Profile Created!", "Success!", MessageBoxButtons.OK, MessageBoxIcon.Asterisk)
conn.Close()
Catch ex As Exception
' here
MsgBox(ex.Message)
End Try