如何从MATLAB中的列表中获取最常用的值（但是多个值）？

From 1 dimensional matrix:

从1维矩阵：

list_A = [1,2,4,6,7,7,7,9,10,11,11,11,13,13,13]

How can i get the list of number that have a highest occurrence (in this case occurrence = 3)

如何获得出现次数最多的数字列表（在本例中为occurrence = 3）

The answer that i want should be like this (if we use list_A):

我想要的答案应该是这样的（如果我们使用list_A）：

Ans = [7,11,13]

2 个解决方案

#1

use hist:

使用hist：

I assumed your vector A is sorted.

我假设您的矢量A已排序。

A = [1,2,4,6,7,7,7,9,10,11,11,11,13,13,13];
occ = 3;

out = A( hist(A,A) == occ )

gives:

得到：

out =

     7    11    13

If A is not sorted, you could sort it of course, or:

如果A未排序，您可以对其进行排序，或者：

A = [7,7,7,1,2,4,6,9,10,11,11,11,13,13,13]
occ = 3;

out = find( histc(A,1:max(A)) == occ )

If there are also negative numbers:

如果还有负数：

A = [7,7,7,-4,6,-9,10,-11,-11,-11,13,13,13,-20]
occ = 3;

out = find( histc(A,min(A):max(A)) == occ ) + min(A)-1

or the simple version is working too:

或简单版本也在工作：

A = sort(A);
out = A( hist(A,A) == occ )

>> out =  -11     7    13

Another convenient way is to use the tabulate function of the Statistics Toolbox, which would even work for decimal values!

另一种方便的方法是使用统计工具箱的制表功能，它甚至可用于十进制值！

A = [7.5,7.5,7.5,-4,6,-9,10,-11,-11,-11,13,13,13,-20]
occ = 3;

T = tabulate(A);
out = T(T(:,2) == occ  ,1)

>> out =

  -11.0000
    7.5000
   13.0000

#2

You can do it most easily with mode. To get all values you should use the third output, which will be a cell array:

您可以使用模式轻松完成。要获取所有值，您应该使用第三个输出，它将是一个单元格数组：

[~, ~, result] = mode(list_A);
result = result{1}.';

EDIT

编辑

If your vector is already sorted and you want to exploit that (which mode apparently doesn't do), you can do it manually with diff, find and max:

如果您的矢量已经排序并且您想要利用它（哪种模式显然不起作用），您可以使用diff，find和max手动执行：

ii = find(diff([list_A inf]));
dii = diff(ii);
result = list_A(ii(find(dii==max(dii))+1));

#1