I have a table name wp_postmeta and some fields one of them is meta_value. I want to input 3 values and check against meta_value field.
我有一个表名wp_postmeta,其中一些字段是meta_value。我想输入3个值并检查meta_value字段。
$price = $_POST['prices'];
$city = $_POST['city'];
$hotels= $_POST['hotels'];
And my query is like
我的查询就像
SELECT post_id,meta_key,meta_value
FROM `wp_postmeta`
WHERE (`meta_value` LIKE '%$price%'
OR `meta_value` LIKE '%$hotels%'
OR `meta_value` LIKE '%$city%')
AND (meta_value IS NOT NULL)
Here if i give 3 inputs then it will be ok, if i left one field empty to compare 2 input values against meta_value then it will list all rows
Any idea?? please share.
这里如果我给3个输入那么它就没问题,如果我将一个字段留空以比较2个输入值与meta_value然后它将列出所有行任何想法?请分享。
3 个解决方案
#1
1
Try,
尝试,
$query = "SELECT post_id,meta_key,meta_value
FROM `wp_postmeta` ";
$where = '';
if(trim($price) != '') {
$where .= "`meta_value` LIKE '%$price%' ";
}
if(trim($hotels) != '') {
if($where != '') $where .= " OR ";
$where .= " `meta_value` LIKE '%$hotels%' ";
}
if(trim($city) != '') {
if($where != '') $where .= " OR ";
$where .= "`meta_value` LIKE '%$city%'";
}
if(trim($where) != '') {
$where = " WHERE ($where) AND (meta_value IS NOT NULL)";
} else {
$where = " WHERE (meta_value IS NOT NULL)";
}
$query = $query.$where;
And, try using $query
in place of actual query in php.
并且,尝试使用$ query代替php中的实际查询。
#2
0
To compare against less than all three, completely remove the portion of the where clause applicable to the variable you're not comparing:
要与少于全部三个进行比较,请完全删除适用于您未比较的变量的where子句部分:
E.G. to not compare $city:
例如。不比较$ city:
SELECT post_id,meta_key,meta_value
FROM `wp_postmeta`
WHERE (`meta_value` LIKE '%$price%'
OR `meta_value` LIKE '%$hotels%')
AND (meta_value IS NOT NULL)
#3
0
One way to do this is with your variable assignment:
一种方法是使用变量赋值:
$price = $_POST['prices'];
$city = $_POST['city'];
$hotels= $_POST['hotels'];
Change to:
改成:
$price = (isset($_POST['prices']) && trim($_POST['prices']) != '' ? filter_var($_POST['prices'],FILTER_VALIDATE_STRING) : null);
I used null, but you could use another value that would guarantee a non-match.
我使用null,但你可以使用另一个值来保证不匹配。
Also, as mentioned in other comments, be sure to use prepared statements.
另外,如其他评论中所述,请务必使用预准备语句。
#1
1
Try,
尝试,
$query = "SELECT post_id,meta_key,meta_value
FROM `wp_postmeta` ";
$where = '';
if(trim($price) != '') {
$where .= "`meta_value` LIKE '%$price%' ";
}
if(trim($hotels) != '') {
if($where != '') $where .= " OR ";
$where .= " `meta_value` LIKE '%$hotels%' ";
}
if(trim($city) != '') {
if($where != '') $where .= " OR ";
$where .= "`meta_value` LIKE '%$city%'";
}
if(trim($where) != '') {
$where = " WHERE ($where) AND (meta_value IS NOT NULL)";
} else {
$where = " WHERE (meta_value IS NOT NULL)";
}
$query = $query.$where;
And, try using $query
in place of actual query in php.
并且,尝试使用$ query代替php中的实际查询。
#2
0
To compare against less than all three, completely remove the portion of the where clause applicable to the variable you're not comparing:
要与少于全部三个进行比较,请完全删除适用于您未比较的变量的where子句部分:
E.G. to not compare $city:
例如。不比较$ city:
SELECT post_id,meta_key,meta_value
FROM `wp_postmeta`
WHERE (`meta_value` LIKE '%$price%'
OR `meta_value` LIKE '%$hotels%')
AND (meta_value IS NOT NULL)
#3
0
One way to do this is with your variable assignment:
一种方法是使用变量赋值:
$price = $_POST['prices'];
$city = $_POST['city'];
$hotels= $_POST['hotels'];
Change to:
改成:
$price = (isset($_POST['prices']) && trim($_POST['prices']) != '' ? filter_var($_POST['prices'],FILTER_VALIDATE_STRING) : null);
I used null, but you could use another value that would guarantee a non-match.
我使用null,但你可以使用另一个值来保证不匹配。
Also, as mentioned in other comments, be sure to use prepared statements.
另外,如其他评论中所述,请务必使用预准备语句。