I have the following array
我有下面的数组。
a=[["kvm16", "one-415"], ["kvm16", "one-416"], ["kvm5", "one-417"]]
I would like to convert this to a hash that looks like this
我想把它转换成这样的哈希
{"kvm5"=>["one-417"], "kvm16"=>["one-417", "one-416"]}
everything I have tried squashes the value.
我所尝试过的每一件事都在贬低它的价值。
v=Hash[ a.collect do |p| [p[0], [ p[1] ] ] end ]
=> {"kvm5"=>["one-417"], "kvm16"=>["one-416"] }
I was thinking I could check to see if v[p[0]] is an array, but the variable isn't defined inside this block.
我想我可以检查一下v[0]是否为一个数组,但是变量在这个块中没有定义。
Is there a clean way to accomplish what I am looking for?
有没有一种干净的方式来完成我想要的?
3 个解决方案
#1
5
Yeah, you have to do it yourself, I'm afraid.
是的,恐怕你得自己动手。
a = [["kvm16", "one-415"], ["kvm16", "one-416"], ["kvm5", "one-417"]]
h = a.each_with_object({}) do |(k, v), memo|
(memo[k] ||= []) << v
end
h # => {"kvm16"=>["one-415", "one-416"], "kvm5"=>["one-417"]}
Or, if you're on older ruby (1.8.x):
或者,如果你使用的是旧ruby (1.8.x):
h = {}
a.each do |k, v|
(h[k] ||= []) << v
end
h # => {"kvm16"=>["one-415", "one-416"], "kvm5"=>["one-417"]}
#2
4
Let's see some functional approaches. This is a common abstraction, you can find it as Enumerable#map_by in Facets:
让我们看看一些功能方法。这是一个常见的抽象,您可以在facet中找到可枚举的#map_by:
require 'facets'
hs.map_by { |k, v| [k, v] }
#=> {"kvm16"=>["one-415", "one-416"], "kvm5"=>["one-417"]}
This pattern replaces the cumbersome group_by
+ map
+ Hash
:
此模式将替换笨重的group_by + map +散列:
Hash[hs.group_by(&:first).map { |k, gs| [k, gs.map(&:last)] }]
#=> {"kvm16"=>["one-415", "one-416"], "kvm5"=>["one-417"]}
#3
0
this has it. in the face of not having each_with_object in my version of ruby and some googleze I arrived at
这它。在我的ruby版本中没有each_with_object,还有一些googleze。
{}.tap{ |h| items.each{ |item| h[item.id] = item } }
=> {"kvm5"=>["one-417"], "kvm16"=>["one-415", "one-416"]}
mucho thanks to Sergio for getting me thinking along that line
感谢塞尔吉奥让我沿着这条线思考。
#1
5
Yeah, you have to do it yourself, I'm afraid.
是的,恐怕你得自己动手。
a = [["kvm16", "one-415"], ["kvm16", "one-416"], ["kvm5", "one-417"]]
h = a.each_with_object({}) do |(k, v), memo|
(memo[k] ||= []) << v
end
h # => {"kvm16"=>["one-415", "one-416"], "kvm5"=>["one-417"]}
Or, if you're on older ruby (1.8.x):
或者,如果你使用的是旧ruby (1.8.x):
h = {}
a.each do |k, v|
(h[k] ||= []) << v
end
h # => {"kvm16"=>["one-415", "one-416"], "kvm5"=>["one-417"]}
#2
4
Let's see some functional approaches. This is a common abstraction, you can find it as Enumerable#map_by in Facets:
让我们看看一些功能方法。这是一个常见的抽象,您可以在facet中找到可枚举的#map_by:
require 'facets'
hs.map_by { |k, v| [k, v] }
#=> {"kvm16"=>["one-415", "one-416"], "kvm5"=>["one-417"]}
This pattern replaces the cumbersome group_by
+ map
+ Hash
:
此模式将替换笨重的group_by + map +散列:
Hash[hs.group_by(&:first).map { |k, gs| [k, gs.map(&:last)] }]
#=> {"kvm16"=>["one-415", "one-416"], "kvm5"=>["one-417"]}
#3
0
this has it. in the face of not having each_with_object in my version of ruby and some googleze I arrived at
这它。在我的ruby版本中没有each_with_object,还有一些googleze。
{}.tap{ |h| items.each{ |item| h[item.id] = item } }
=> {"kvm5"=>["one-417"], "kvm16"=>["one-415", "one-416"]}
mucho thanks to Sergio for getting me thinking along that line
感谢塞尔吉奥让我沿着这条线思考。