如何用两个大小相等的数组构建Ruby散列?

时间:2021-09-02 12:54:19

I have two arrays

我有两个数组

a = [:foo, :bar, :baz, :bof]

and

b = ["hello", "world", 1, 2]

I want

我想要的

{:foo => "hello", :bar => "world", :baz => 1, :bof => 2}

Any way to do this?

有什么办法吗?

3 个解决方案

#1


174  

h = Hash[a.zip b] # => {:baz=>1, :bof=>2, :bar=>"world", :foo=>"hello"}

...damn, I love Ruby.

…该死,我爱Ruby。

#2


27  

Just wanted to point out that there's a slightly cleaner way of doing this:

我想指出的是,有一种更清洁的方法:

h = a.zip(b).to_h # => {:foo=>"hello", :bar=>"world", :baz=>1, :bof=>2}

Have to agree on the "I love Ruby" part though!

但是我必须同意“我爱Ruby”这部分!

#3


13  

How about this one?

这一个怎么样?

[a, b].transpose.to_h

If you use Ruby 1.9:

如果你使用Ruby 1.9:

Hash[ [a, b].transpose ]

I feel a.zip(b) looks like a is master and b is slave, but in this style they are flat.

我觉得a.zip(b)看起来a是master, b是slave,但在这种风格下,它们是扁平的。

#1


174  

h = Hash[a.zip b] # => {:baz=>1, :bof=>2, :bar=>"world", :foo=>"hello"}

...damn, I love Ruby.

…该死,我爱Ruby。

#2


27  

Just wanted to point out that there's a slightly cleaner way of doing this:

我想指出的是,有一种更清洁的方法:

h = a.zip(b).to_h # => {:foo=>"hello", :bar=>"world", :baz=>1, :bof=>2}

Have to agree on the "I love Ruby" part though!

但是我必须同意“我爱Ruby”这部分!

#3


13  

How about this one?

这一个怎么样?

[a, b].transpose.to_h

If you use Ruby 1.9:

如果你使用Ruby 1.9:

Hash[ [a, b].transpose ]

I feel a.zip(b) looks like a is master and b is slave, but in this style they are flat.

我觉得a.zip(b)看起来a是master, b是slave,但在这种风格下,它们是扁平的。