I'm using SQL Server and TSQL:
我使用的是SQL Server和TSQL:
What I would like to do is comma separate values on one column when using a group by on another column. See data example below.
我想做的是,当在另一列上使用group by时,在一列上用逗号分隔值。请参阅下面的示例数据。
col1 --- col2 1121 abc 1123 aee 1335 afg 1121 def 1121 abc
I would like to Group By on "col1" and count the number of records, but I would also like to concatenate on col2 if the data is different. For instance, using value "1121" as a reference, see the data output below.
我想在“col1”上分组并计算记录的数量,但如果数据不同,我也想在col2上进行连接。例如,使用值“1121”作为引用,请参阅下面的数据输出。
qty --- col1 --- col2 3 1121 abc, def 1 1123 aee 1 1335 afg
I thought of maybe using COALESCE, but I'm not sure how to implement it when using group by on another column.
我想过可能使用COALESCE,但我不确定在另一篇专栏文章中使用group by时如何实现它。
Any help would be greatly appreciated.
如有任何帮助,我们将不胜感激。
1 个解决方案
#1
5
Here's a complete, tested, working example.
这里有一个完整的、经过测试的、工作的示例。
create table tmp (col1 varchar(100), col2 varchar(100));
insert into tmp values ('1121', 'abc');
insert into tmp values ('1123', 'aee');
insert into tmp values ('1335', 'afg');
insert into tmp values ('1121', 'def');
insert into tmp values ('1121', 'abc');
SELECT
distinct r.col1,
STUFF((SELECT distinct ','+ a.col2
FROM tmp a
WHERE r.col1 = a.col1
FOR XML PATH(''), TYPE).value('.','VARCHAR(max)'), 1, 1, ''),
(select COUNT(*) cnt from tmp a where r.col1 = a.col1) cnt
FROM tmp r
Result
结果
1121 abc,def 3
1123 aee 1
1335 afg 1
References: Used OMG Ponies' answer here as a guide.
参考资料:使用OMG小马的回答作为指南。
#1
5
Here's a complete, tested, working example.
这里有一个完整的、经过测试的、工作的示例。
create table tmp (col1 varchar(100), col2 varchar(100));
insert into tmp values ('1121', 'abc');
insert into tmp values ('1123', 'aee');
insert into tmp values ('1335', 'afg');
insert into tmp values ('1121', 'def');
insert into tmp values ('1121', 'abc');
SELECT
distinct r.col1,
STUFF((SELECT distinct ','+ a.col2
FROM tmp a
WHERE r.col1 = a.col1
FOR XML PATH(''), TYPE).value('.','VARCHAR(max)'), 1, 1, ''),
(select COUNT(*) cnt from tmp a where r.col1 = a.col1) cnt
FROM tmp r
Result
结果
1121 abc,def 3
1123 aee 1
1335 afg 1
References: Used OMG Ponies' answer here as a guide.
参考资料:使用OMG小马的回答作为指南。