Underscore.js - 获取唯一的属性值

I only recently discovered the power of underscore.js, still new to the methods I kindly ask for a suggestion:

我最近才发现了underscore.js的强大功能，对我提出建议的方法还是新手：

How do I get from this:

我如何从中得到：

[
    [{
        "name": "Type 2",
        "id": 14
    }],
    [{
        "name": "Type 1",
        "id": 13
    }, {
        "name": "Type 3",
        "id": 15
    }],
    [{
        "name": "Type 2",
        "id": 14
    }],
    [{
        "name": "Type 1",
        "id": 13
    }]
]

to this:

对此：

["Type 1","Type 2","Type 3"]

i.e. no duplicated and "name" property only.

即没有重复和“名称”属性。

Any suggestions much appreciated.

任何建议非常感谢。

5 个解决方案

#1

_(data).chain().flatten().pluck('name').unique().value()

(Convert the nested lists to a flat one, pick name from each of the objects in the list, and make it unique.)

（将嵌套列表转换为平面列表，从列表中的每个对象中选择名称，并使其唯一。）

#2

Use flatten first, to convert the nested array to a flat array.
首先使用展平，将嵌套数组转换为平面数组。
Then pluck to get the "name" values as an array
然后采取将“名称”值作为数组
Finally uniq
最后是uniq

_.uniq(_.pluck(_.flatten(items), "name"))

Fiddle

小提琴

#3

var arr = _.uniq(_.map(_.flatten(array), function(e) {
    return e.name;
}));

#4

_.uniq(_.pluck(x,'name'));

the above code is sufficient for extracting different "name" attribute

上面的代码足以提取不同的“名称”属性

#5

Simple way:

简单方法：

1. use _.map to get all the names

1.使用_.map获取所有名称

var names = _.map(items, function(item) { return item.name});

2. Get the _.uniq from that names

2.从这些名称中获取_.uniq

var uniqueNames = _.uniq(names);

#1

_(data).chain().flatten().pluck('name').unique().value()