ReferenceError:在尝试使用函数组合时，没有定义错误

I have defined two simple functions in nodejs:

我在node . js中定义了两个简单的函数:

function findEntityDetailsAsIs(modelname, callback) {
     modelname.find({}, function(error, result) {
         if (error)
           callback (error, null);
         else {
           //console.log(result);
           callback (null, result);
         }
    });
};

This is my first function and another function is

这是第一个函数，另一个函数是

function printEntitydetails(error, entitydetails, callback) {
   console.log(entitydetails);
}

I am trying to call these functions as such

我试着把这些函数称为。

findEntityDetailsAsIs(fieldLabel, printEntitydetails(error, entitydetails));

But as i try to run this function call it throws an error

但是当我尝试运行这个函数时它会抛出一个错误

ReferenceError: error is not defined

But error is just as placeholder object i am passing from callback.

但是error只是我从回调中传递的占位符对象。

 findEntityDetailsAsIs(fieldLabel, printEntitydetails(entitydetails));

I tried skipping error in the call but this time it gives this error.

我尝试在调用中跳过错误，但这次它给出了这个错误。

ReferenceError: entitydetails not  is not defined

As per my knowledge the findEntityDetailsAsIs should provide the context for the entitydetails, as i have provided a callback(null, result).

据我所知，findEntityDetailsAsIs应该为entitydetails提供上下文，因为我提供了回调(null, result)。

1 个解决方案

#1

Your function findEntityDetailsAsIs expects to get the callback function, not the execution result of it.
You need to provide only the function name:

函数findEntityDetailsAsIs希望获得回调函数，而不是它的执行结果。您只需要提供函数名:

 findEntityDetailsAsIs(fieldLabel, printEntitydetails);

When you run it like you do, you pass to findEntityDetailsAsIs the result of printEntitydetails instead of the function itself. since the function returns nothing, you get undefined

当您像这样运行它时，您将把printEntitydetails而不是函数本身的结果传递给findEntityDetailsAsIs。由于函数没有返回任何内容，所以您将没有定义。

#1