如何合并两个对象数组并连接值？

I have this two array of objects

我有这两个对象数组

var client = [{
        "creazione": "1970-01-01",
        "value": 2
    }, {
        "creazione": "2014-03-12",
        "value": 4
    }, {
        "creazione": "2014-03-14",
        "value": 1
    }],
    order = [{
        "creazione": "1970-01-01",
        "value": 1
    }, {
        "creazione": "2014-03-13",
        "value": 5
    }, {
        "creazione": "2014-03-14",
        "value": 1
    }];

I need to merge these two arrays to get something like:

我需要合并这两个数组来得到类似的东西：

 [{
     x: '1970-01-01',
     y: [2, 1]
 }, {
     x: '2014-03-12',
     y: [4, 0]
 }, {
     x: '2014-03-14',
     y: [1, 1]
 }, {
     x: '2014-03-13',
     y: [0, 5]
 }]

In few words I need to check if a.creazione == b.creazione then merge the key and concat the values in an array (first line of result), else if it is different, assign the value of the existing array in the right position of the y array (third line of result).

用几句话我需要检查a.creazione == b.creazione然后合并密钥并将数值连接到数组（结果的第一行），否则如果它不同，则在右边分配现有数组的值y数组的位置（结果的第三行）。

PS: I need to get this structure beacuse I'm using Angular-Charts library, and it ask for data in this uncomfortable way.

PS：我需要得到这个结构，因为我正在使用Angular-Charts库，它以这种不舒服的方式询问数据。

Any idea on how to achieve this?

有关如何实现这一点的任何想法？

2 个解决方案

#1

Using plain JavaScript:

使用纯JavaScript：

var result = [];
client.forEach( function( entry ) {
    for( var i = 0; i < order.length; ++i ) {
        if( entry.creazione === order[i].creazione ) {
            result.push( { x: entry.creazione, y: [ entry.value, order[i].value ] } );
            order.splice( i, 1 );
            return;
        }
    }
    result.push( { x: entry.creazione, y: [ entry.value, 0 ] } );
} );
order.forEach( function( entry ) {
    result.push( { x: entry.creazione, y: [ 0, entry.value ] } );
} );

Fiddle: http://jsfiddle.net/rPk6e/

小提琴：http：//jsfiddle.net/rPk6e/

Note that for simplicity the order array is modified. If that is a problem for your use case simply make a copy using slice.

请注意，为简单起见，修改了顺序数组。如果这是您的用例的问题，只需使用切片进行复制。

#2

Allow me to amuse you with the power of functional programming :)

请允许我用功能编程的力量来娱乐你:)

client = _.object(_.map(client, _.values));
order  = _.object(_.map(order , _.values));
var result = _
    .chain(_.keys(client))
    .union(_.keys(order))
    .map(function (key) {
        return [key, [client[key] || 0, order[key] || 0]];
    })
    .map(_.partial(_.zipObject, ['x', 'y']))
    .value();
console.log(result);
# [ { x: '1970-01-01', y: [ 2, 1 ] },
#   { x: '2014-03-12', y: [ 4, 0 ] },
#   { x: '2014-03-14', y: [ 1, 1 ] },
#   { x: '2014-03-13', y: [ 0, 5 ] } ]

#1