如何在忽略键的情况下组合两个PHP数组

Thought this was an easy one, but after Googling around for awhile, I've come up short. I need to combine two PHP arrays while ignoring the keys:

认为这是一个简单的，但谷歌搜索了一段时间后，我已经做空了。我需要组合两个PHP数组而忽略键：

array(
  0 => 'Word 1',
  1 => 'Word 2'
)

array(
  0 => 'Word 3',
  1 => 'Word 4',
  2 => 'Word 5'
)

Result should be:

结果应该是：

array(
  0 => 'Word 1',
  1 => 'Word 2',
  2 => 'Word 3',
  3 => 'Word 4',
  4 => 'Word 5'
)

Tried array_merge but that replaces duplicate keys. array_combine won't work because it requires the same numer of elements in both array.

尝试使用array_merge但替换了重复的键。 array_combine不起作用，因为它需要两个数组中相同数量的元素。

2 个解决方案

#1

array_merge should do the trick. If it doesn't, meaning your keys are probably not numeric. Try converting them into plain values based arrays first, then merge them.

array_merge应该做的伎俩。如果没有，则意味着您的密钥可能不是数字。首先尝试将它们转换为基于普通值的数组，然后合并它们。

array_merge(array_values($a), array_values($b))

Should do the trick.

应该做的伎俩。

Sample: https://3v4l.org/chuXV

示例：https：//3v4l.org/chuXV

array_values: http://php.net/manual/en/function.array-values.php

array_values：http：//php.net/manual/en/function.array-values.php

#2

-1

//Try using two for loops to copy the data over to a third array like this.   
<?php
       $a1 = array(
         0 => 'w1', 
         1 => 'w2'
       );
       $a2 = array(
         0 => 'w3', 
         1 => 'w4', 
         2 => 'w5'
       );



      $counter = 0;

      for($i = 0; $i < count($a1); $i++){
        $a3[$counter] = $a1[$i];
        $counter++;
      }
      for($i = 0; $i < count($a2); $i++){
        $a3[$counter] = $a2[$i];
        $counter++;
      }
      print_r($a3);
?>

#1