如果返回结果数组，如何获取json的值？

时间：2022-10-11 12:16:42

I want to know how can I retrieve the values from the json if the json returns an array of result?

我想知道如果json返回结果数组,我如何从json中检索值?

Note: the first array is not the same length of the second array but the first array is will be always be less than the second array

注意:第一个数组与第二个数组的长度不同,但第一个数组总是小于第二个数组

Here's what I do as of now and get this error:

这是我现在所做的,并得到此错误:

如果返回结果数组，如何获取json的值？

Here's my jquery code:

这是我的jquery代码:

success: function(data){
            var toAppend = '';
            if(typeof data === "object"){
                for(var i=0;i<data.length;i++){
                    toAppend += '<tr><td colspan="2">'+data[0][i]['m-asin'][0]+'</td></tr>';
                    toAppend += '<tr><td>'+data[1][i]['asin'][0]+'</td><td>'+data[1][i]['size'][0]+'</td></tr>';
                }
                $('.data-results').append(toAppend);
            }
        }

ANd I think no need for php code since it is working because it returns the expected results. Any help will be a big thing thanks!

我认为不需要PHP代码,因为它正在工作,因为它返回预期的结果。任何帮助都将是一件大事,谢谢!

1 个解决方案

#1

2  

data[0][i] gives you the i-th property of the first data element. You'll need to revert it: data[i][0].

data [0] [i]为您提供第一个数据元素的第i个属性。你需要还原它:data [i] [0]。

Or otherwise, you'll need to alter the loop, to get the number of elements in data[0]:

或者,您需要更改循环,以获取data [0]中的元素数量:

for(var i=0; i<data[0].length; i++){

#1

2  

data[0][i] gives you the i-th property of the first data element. You'll need to revert it: data[i][0].

data [0] [i]为您提供第一个数据元素的第i个属性。你需要还原它:data [i] [0]。

Or otherwise, you'll need to alter the loop, to get the number of elements in data[0]:

或者,您需要更改循环,以获取data [0]中的元素数量:

for(var i=0; i<data[0].length; i++){
标签：

相关文章