两个数组:如果第一个数组中的键为空，那么将第二个数组中的相同键设置为空?

I have this array that has two $rows:

这个数组有两个$行:

I'd like the second array's display to be based on the first array but I don't think I have it set up properly:

我希望第二个数组的显示基于第一个数组，但是我认为我没有正确地设置它:

$rows = &$vars['rows'];
foreach ($rows[0] as $key => $value) {
  if (strpos($key, 'views') === 0 && empty($value)) {
        $rows[1][$key] = '';
        unset($vars['header'][$key]);
  }
}

This is the output from the code, you can see the table doesn't seem aligned properly:

这是来自代码的输出，你可以看到表格似乎不对齐:

1 个解决方案

#1

You need to loop over the whole array and then loop over the inner data as well. Simply you need two foreach loops.

您需要对整个数组进行循环，然后对内部数据进行循环。你只需要两个foreach循环。

$rows = $vars;
foreach ($rows as $occ => $outer ) {
    foreach ($outer as $key => $value) {
        if (strpos($key, 'views') === 0 && $value =='') {
            unset($vars[$occ][$key]);
        }
    }
}