I am creating a audio file uploading system for my project. In this case I am using angularjs app and I use html too. I have written the back end of my application using the google app engine. In this case the problem I found was I followed the google blobstore api and I did the file uploading using a jsp page. But I want to get it done by and html page. And the problem is that there is a java code in the jsp which makes a call to createUploadUrl method in the blobstore api. But in a html page I cannot do it. I tried to do it in the following way using angularjs.
我正在为我的项目创建一个音频文件上传系统。在本例中,我使用的是angularjs应用程序,我也使用html。我已经使用谷歌应用程序引擎编写了应用程序的后端。在本例中,我发现的问题是我遵循谷歌blobstore api并使用jsp页面上传文件。但是我想通过html页面完成。问题是jsp中有一个java代码,它在blobstore api中调用createUploadUrl方法。但在html页面中,我做不到。我试着使用angularjs以以下方式来做。
<div class="container">
<h1>Audio Upload</h1>
<form method="post" enctype="multipart/form-data">
<input type="text" name="foo" ng-model="audio.foo"/>
<input type="file" name="myFile" ng-model="audio.myFile"/>
<input type="submit" value="Submit" ng-click="upload(audio)"/>
</form>
</div>
here is the code for the html page.
这是html页面的代码。
And the following is the controller for the html page.
下面是html页面的控制器。
function AudioUpload( $http,$filter, $timeout, $scope, $location, $rootScope) {
console.log("=========================");
console.log("Audio Upload Controller...");
$scope.upload = function(audio) {
$('.line-loader').show();
$http({
url : '/upload',
method : "POST",
//data : $.param(audio),
headers : {
'Content-Type' : 'audio/mp3; charset=UTF-8'
}
}).success(function(data) {
console.log(audio.myFile+"Audio Successfully Uploaded...")
})
}
}
And here are the servlets that are being used to get this task done
这里是用于完成此任务的servlet
Serve Servlet
服务Servlet
package xxx.xxxx.fileupload;
import java.io.IOException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import com.google.appengine.api.blobstore.BlobKey;
import com.google.appengine.api.blobstore.BlobstoreService;
import com.google.appengine.api.blobstore.BlobstoreServiceFactory;
public class Serve extends HttpServlet {
private BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService();
@Override
public void doGet(HttpServletRequest req, HttpServletResponse res)
throws IOException {
BlobKey blobKey = new BlobKey(req.getParameter("blob-key"));
blobstoreService.serve(blobKey, res);
}
}
Upload Servlet
上传Servlet
package xxx.xxxxx.fileupload;
import java.io.IOException;
import java.util.List;
import java.util.Map;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import com.google.appengine.api.blobstore.BlobKey;
import com.google.appengine.api.blobstore.BlobstoreService;
import com.google.appengine.api.blobstore.BlobstoreServiceFactory;
public class Upload extends HttpServlet {
private BlobstoreService blobstoreService = BlobstoreServiceFactory
.getBlobstoreService();
@Override
public void doPost(HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException {
Map<String, List<BlobKey>> blobs = blobstoreService.getUploads(req);
List<BlobKey> blobKeys = blobs.get("myFile");
if (blobKeys == null || blobKeys.isEmpty()) {
res.sendRedirect("/");
} else {
res.sendRedirect("/serve?blob-key="
+ blobKeys.get(0).getKeyString());
}
}
}
I need to get upload the file using an html page and this is the code that is in the index.jsp page which works fine with these servlets.
我需要使用html页面上传文件,这是索引中的代码。jsp页面使用这些servlet很好。
Index.jsp
index . jsp
<%@ page import="com.google.appengine.api.blobstore.BlobstoreServiceFactory" %>
<%@ page import="com.google.appengine.api.blobstore.BlobstoreService" %>
<%
BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService();
%>
<html>
<head>
<meta http-equiv="Content-Type" content="audio/mp3; charset=ISO-8859-1">
<title>Upload Test</title>
</head>
<body>
<form action="<%= blobstoreService.createUploadUrl("/upload1") %>" method="post" enctype="multipart/form-data">
<input type="text" name="foo">
<input type="file" name="myFile">
<input type="submit" value="Submit">
</form>
</body>
</html>
Can anybody please help me to complete my code using angularjs and html without using jsp. Thank you.
谁能帮我在不使用jsp的情况下使用angularjs和html完成我的代码吗?谢谢你!
1 个解决方案
#1
2
Angular doesn't yet support file inputs yet, so you need a directive to get the file from the input. The file can be assigned to the controller, then you can conduct the upload with $http from there.
角还不支持文件输入,所以需要一个指令从输入中获取文件。可以将文件分配给控制器,然后您可以使用$http进行上传。
(function(){
angular.module('app',[]);
angular.module('app')
.controller('FileCtrl', FileCtrl)
.directive('fileDirective', fileDirective);
function FileCtrl(){
var vm = this;
vm.myFile;
vm.upload = function(){
// upload stuff goes here
}
}
fileDirective.$inject = ['$log'];
function fileDirective($log){
var directive = {
restrict: 'A',
link: link,
scope: {
fileDirective: '=fileDirective',
file: '=name'
}
}
return directive;
function link(scope, element, attrs, controller){
$log.debug(scope);
element.bind('change', function(){
var fileSelected = element[0].files[0];
$log.debug(fileSelected);
scope.$apply(function () {
scope.file = fileSelected;
$log.debug(scope.file);
});
});
}
}
})()
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="app" class="container" ng-controller="FileCtrl as audio">
<h1>Audio Upload</h1>
<form method="post" enctype="multipart/form-data">
<input type="text" name="foo" ng-model="audio.foo"/>
<input type="file" name="audio.myFile" file-Directive="audio.myFile"/>
<input type="submit" value="Submit" ng-click="audio.upload(audio)"/>
</form>
<p>Your file name is: {{audio.myFile.name}}</p>
</div>
#1
2
Angular doesn't yet support file inputs yet, so you need a directive to get the file from the input. The file can be assigned to the controller, then you can conduct the upload with $http from there.
角还不支持文件输入,所以需要一个指令从输入中获取文件。可以将文件分配给控制器,然后您可以使用$http进行上传。
(function(){
angular.module('app',[]);
angular.module('app')
.controller('FileCtrl', FileCtrl)
.directive('fileDirective', fileDirective);
function FileCtrl(){
var vm = this;
vm.myFile;
vm.upload = function(){
// upload stuff goes here
}
}
fileDirective.$inject = ['$log'];
function fileDirective($log){
var directive = {
restrict: 'A',
link: link,
scope: {
fileDirective: '=fileDirective',
file: '=name'
}
}
return directive;
function link(scope, element, attrs, controller){
$log.debug(scope);
element.bind('change', function(){
var fileSelected = element[0].files[0];
$log.debug(fileSelected);
scope.$apply(function () {
scope.file = fileSelected;
$log.debug(scope.file);
});
});
}
}
})()
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="app" class="container" ng-controller="FileCtrl as audio">
<h1>Audio Upload</h1>
<form method="post" enctype="multipart/form-data">
<input type="text" name="foo" ng-model="audio.foo"/>
<input type="file" name="audio.myFile" file-Directive="audio.myFile"/>
<input type="submit" value="Submit" ng-click="audio.upload(audio)"/>
</form>
<p>Your file name is: {{audio.myFile.name}}</p>
</div>