如何比较两个字节数组[重复]

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这个问题在这里已有答案：

Comparing two byte arrays in .NET 28 answers
在.NET 28答案中比较两个字节数组

I have two byte arrays with the exact same content. I tried:

我有两个字节数组，内容完全相同。我试过了：

if (bytearray1 == bytearray2) {...} else {...}

and

和

if (Array.Equals(bytearray1, bytearray2)) {....} else {...}

All time it goes to the else! I don't know why! I checked both arrays manually several times!!!

一直到别的地方！我不知道为什么！我手动检查了两个阵列几次！

4 个解决方案

#1

Try using the SequenceEqual extension method. For example:

尝试使用SequenceEqual扩展方法。例如：

byte[] a1 = new byte[] { 1, 2, 3 };
byte[] a2 = new byte[] { 1, 2, 3 };
bool areEqual = a1.SequenceEqual(a2); // true

#2

The == operator compares by reference; those are two different instances.

==运算符通过引用进行比较;这是两个不同的例子。

Array.Equals is really Object.Equals, which calls the instances Equals method.
Since arrays do not override Equals(), this too compares by reference.

Array.Equals实际上是Object.Equals，它调用实例Equals方法。由于数组不会覆盖Equals（），因此也通过引用进行比较。

Instead, you should call the LINQ SequenceEqual() method.

相反，您应该调用LINQ SequenceEqual（）方法。

#3

Both the == operator and the Equals method will test reference equality. Since you have two separate arrays, they will never be equal.

==运算符和Equals方法都将测试引用相等性。由于你有两个独立的数组，它们永远不会相等。

Since you want to test that both arrays have the same content in the same order, try using the SequenceEqual method instead.

由于您要测试两个阵列具有相同顺序的相同内容，请尝试使用SequenceEqual方法。

#4

-4

As an alternative, if you are not comfortable using LINQ you can use the System.Convert class...

作为替代方案，如果您不习惯使用LINQ，可以使用System.Convert类...

byte[] a1;
byte[] a2;

if (System.Convert.ToBase64String(a1) == System.Convert.ToBase64String(a2)) {
    doSomething();
}
else {
    doSomethingElse();
}

#1