比较tsql中具有不同值的行

I am using a Microsoft Server-2008 and I have a table like this:

我使用的是Microsoft Server-2008,我有一个这样的表:

Name | Houre | Value
Hst1 | 4 | 45
Hst1 | 5 | 12
Hst1 | 6 | 88
Hst2 | 4 | 82
Hst2 | 5 | 7
Hst2 | 6 | 12

And I want to get something like this:

我希望得到这样的东西:

Name | 4  | 5  | 6 
Hst1 | 45 | 12 | 88
Hst2 | 82 | 7  | 12

Can you help me?

你能帮助我吗?

2 个解决方案

#1

Depending if you only have 4,5,6 you can do a conditional agregation, other wise you need a dynamic PIVOT

如果您只有4,5,6,您可以进行条件聚合,否则您需要动态PIVOT

SELECT Name, 
       MAX(CASE WHEN Houre = 4 THEN Value ELSE 0 END) as [4],
       MAX(CASE WHEN Houre = 5 THEN Value ELSE 0 END) as [5],
       MAX(CASE WHEN Houre = 6 THEN Value ELSE 0 END) as [6]
FROM YourTable
GROUP BY Name

#2

Use PIVOT!

SELECT *
FROM (
  VALUES ('Hst1', 4, 45),
         ('Hst1', 5, 12),
         ('Hst1', 6, 88),
         ('Hst2', 4, 82),
         ('Hst2', 5, 7),
         ('Hst2', 6, 12)
) t(name, hour, value)
PIVOT (
  max(value) FOR hour IN ([4], [5], [6])
) t