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- nodejs arrow function with expression [duplicate] 1 answer
nodejs带有表达式的箭头函数[复制] 1个答案
I want to convert one array to another kind of array. Actually I am using typescript. What am I doing wrong here:
我想将一个数组转换为另一种数组。其实我正在使用打字稿。我在这做错了什么:
//terminals is an array of objects.
groupOptions = terminals.map(trm => {
id: trm.TerminalID,
text: trm.TerminalName,
selected: true
});
intelisence complains about the body of the curly brackets. With them I meant an object, probably intellisence thinks its anonymous method body. How can I workaround this?
知识分子抱怨大括号的主体。有了它们,我的意思是一个对象,可能是intellisence认为它的匿名方法体。我该如何解决这个问题?
1 个解决方案
#1
2
Try wrapping the curly brackets with parenthesis like this:
尝试用括号括起大括号,如下所示:
//terminals is an array of objects.
groupOptions = terminals.map(trm => ({
id: trm.TerminalID,
text: trm.TerminalName,
selected: true
}) );
Problem is that the JavaScript runtime picks up the curly brackets as beginning/end of a function.
问题是JavaScript运行时选择大括号作为函数的开头/结尾。
#1
2
Try wrapping the curly brackets with parenthesis like this:
尝试用括号括起大括号,如下所示:
//terminals is an array of objects.
groupOptions = terminals.map(trm => ({
id: trm.TerminalID,
text: trm.TerminalName,
selected: true
}) );
Problem is that the JavaScript runtime picks up the curly brackets as beginning/end of a function.
问题是JavaScript运行时选择大括号作为函数的开头/结尾。